使用正则表达式从字符串中读取多个变量

Question

I'm trying to split a string into different variables. Something like the opposite of String.format() . I want a particular regex to match and then that portion of the string should be assigned to a specific variable. Is that possible using StringReader or any other class?

Example my String is 5 13-DEC-2010 16:47 A Tach 220 380 now it should be assigned to variables like:

1. number = 5
2. date = 13-DEC-2010
3. time = 16:47
4. type = A Tach
5. num1 = 220
6. num2 = 380

where all variables can be strings

Answer 1

Try this:

var s = '5 13-DEC-2010 16:47 A Tach 220 380';
var re = /(\d+)\s+(\d{1,2}-[A-Z]{3}-\d{4})\s+(\d{2}:\d{2})\s+([\w\s+]*)\s+(\d+)\s+(\d+)/
var m = s.match(re);

Answer 2

Base from my past experience, there wasn't any builtin class that will do that. Just manually manipulate your data. Like split it (str.split("\\s");), then stored in they respective variables. But the problem is the case "A Tach".

If you ask me I'll just replace the data seperator(in your case its a space) with a regex that will not occur in your string, something like ";=;" where your string will be transformed into "5;=;13-DEC-2010;=;16:47;=;A Tach;=;220;=;380" Then just split the data and parse it to their respective variable.

Answer 3

public static void main(String[] args) {
    String s = "5 13-DEC-2010 16:47 A Tach 220 380";
    String re = "(\\d+)\\s+(\\d{1,2}-[A-Z]{3}-\\d{4})\\s+(\\d{2}:\\d{2})\\s+([\\w\\s+]*)\\s+(\\d+)\\s+(\\d+)";
    Pattern p = Pattern.compile(re);
    String number=null,date=null,time=null,type=null,num1=null,num2=null;
    Matcher m = p.matcher(s);
    if (m.matches()) {
        number = m.group(1);
        date = m.group(2);
        time = m.group(3);
        type = m.group(4);
        num1 = m.group(5);
        num2 = m.group(6);
    }
    System.out.println(number);
    System.out.println(date);
    System.out.println(time);
    System.out.println(type);
    System.out.println(num1);
    System.out.println(num2);
}