如何从PHP foreach循环中排除隐藏字段

Question

I have a simple form that inserts data into a database using foreach($_POST as $key=>$value) I have a hidden field on the form

<input name="isset" type="hidden" value="true" />

And i use if(isset($_POST['isset'])) {

I'm trying to work out how to exclude the hidden field from the loop ...?

I've looked at this post but don't understand where i would use if (strpos($key, 'hdn_') == false) // proceed

How to exclude <input type="hidden"> from a for each loop in PHP

any guidance would be appreciated....

Answer 1

If you know the exact names of keys you want to exclude, array_diff_key is a convenient option:

$keysToRemove = array('isset'); // you can add as many as you want
$values = array_diff_key($_POST, array_flip($keysToRemove));

foreach ($values as $k => $v) { ... }

However, since $values is intended to go into the database you should use a whitelist of allowed keys instead of a blacklist. You can do that with array_intersect_key :

$keysToKeep = array('field1', 'field2', 'field3'); // as many as you want
$values = array_intersect_key($_POST, array_flip($keysToKeep));

foreach ($values as $k => $v) { ... }

Answer 2

Inside the foreach:

foreach ($_POST as $key => $value) {
    if ($key != 'isset') {
        //code here
    }
}

(For what I got from your question)

Or from your array, you can unset() the element with the 'isset' array key.