如何选择带有数据的所有表行以显示带有数据的总数
[英]How can I SELECT all table rows with data to display total number with data
问题描述
I'm trying to show the total amount of say people with kittens. 
我试图显示说有小猫的人的总数。
$query = mysql_query("SELECT * FROM people.kittens WHERE IS NOT NULL");
The issue is the field is not set to NULL and is either blank or has data. 问题是该字段未设置为NULL并且为空或有数据。 Then I would show the total number with: 然后，我将显示总数：
$Totalpeoplewithkittens = mysql_num_rows($query);
I know mysql_query is outdated. 我知道mysql_query已过时。 Just testing/learning. 只是测试/学习。
2 个解决方案
解决方案1
0 已采纳 2012-11-10 23:12:34
关于什么
$query = mysql_query("SELECT count(kittens) FROM people WHERE kittens > ''");
解决方案2
0 2012-11-10 23:13:36
像从...选择计数（*）一样使用
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