[英]How to shorten a jQuery function?
I have this jQuery function that work. 我有这个jQuery函数可以工作。 Every 2 lines is the same except a minor changes. 除了微小的变化外,每两行是相同的。 How can I shorten it? 我怎样才能缩短它?
$(".c1").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c2").fadeIn("slow", function() {
$(".c2").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c3").fadeIn("slow", function() {
$(".c3").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c4").fadeIn("slow", function() {
$(".c4").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c5").fadeIn("slow", function() {
$(".c5").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c6").fadeIn("slow", function() {
$(".c6").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c7").fadeIn("slow", function() {
$(".c7").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c8").fadeIn("slow", function() {
$(".c8").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c9").fadeIn("slow", function() {
$(".c9").delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c1").fadeIn("slow");
});
});
});
});
});
});
});
});
});
});
});
});
});
});
});
});
});
});
You could use a recursive function like this: 您可以使用这样的递归函数:
function phoneCall(i){
$(".c" + i).delay(5000).fadeOut("slow", function() {
$("#phone").addClass("c" + (i + 1)).fadeIn("slow", function() {
if(i <= 9) phoneCall(i + 1);
});
});
}
phoneCall(1);
It seems that the #phone
element is the only one that ever gets the c_
class. 似乎#phone
元素是唯一一个获得c_
类的元素。 If so, you can cache the element and eliminate a bunch of code. 如果是这样,您可以缓存元素并消除一堆代码。
var phone = $("#phone"), i = 0;
(function cycle() {
i = ((i % 9) + 1);
phone.addClass("c" + i).fadeIn("slow").delay(5000).fadeOut("slow", cycle);
})();
We can even get rid of a line of code by inlining the increment. 我们甚至可以通过内联增量来摆脱一行代码。
var phone = $("#phone"), i = 0;
(function cycle() {
phone.addClass("c" + ((++i % 9) + 1)).fadeIn("slow").delay(5000).fadeOut("slow", cycle);
})();
As @charlietfl noted, you may not want it to infinitely loop. 正如@charlietfl所说,你可能不希望它无限循环。 If not, add a return
statement. 如果没有,请添加一个return
语句。
var phone = $("#phone"), i = 0;
(function cycle() {
if (i === 9) return;
phone.addClass("c" + ((++i % 9) + 1)).fadeIn("slow").delay(5000).fadeOut("slow", cycle);
})();
And FWIW, numbering is usually a little simpler if you use 0
based indices. 而对于FWIW,如果使用基于0
的索引,编号通常会更简单一些。
var phone = $("#phone"), i = -1;
(function cycle() {
phone.addClass("c" + (++i % 9)).fadeIn("slow").delay(5000).fadeOut("slow", cycle);
})();
You can use something like that: 你可以使用这样的东西:
function inception(fromInt, tillInt){
if (fromInt < tillInt){
$('.c' + fromInt).delay(5000).fadeOut("slow",function(){
newInt = fromInt +1;
$('#phone').addClass('c'+newInt).fadeIn("slow", function() {
inception(newInt, tillInt));
}
});
}else{
if(fromint == tillInt){
$('.c' + fromInt).delay(5000).fadeOut("slow");
}
}
}
Then add to your code: 然后添加到您的代码:
inception(1,9);
I don't know something like this? 我不知道这样的事吗?
var num = 2;
var HandlerForC = function () {
if (num < 10) {
$("#phone").addClass("c" + num).fadeIn("slow", HandlerForPhone);
} else {
$("#phone").addClass("c1").fadeIn("slow");
}
}
var HandlerForPhone = function () {
num++;
$(".c" + (num - 1)).delay(5000).fadeOut("slow", HandlerForC);
}
HandlerForPhone();
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