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链接列表删除正在删除错误的节点

[英]Linked list deletion is removing the wrong node

Please I need someone help. 请我帮忙。 I'm having trouble with my homework. 我在做作业时遇到麻烦。

This homework is very simple. 这个作业很简单。 Create a list(1,2,3) and delete the middle number by creating a function delnode . 创建一个list(1,2,3)并通过创建一个函数delnode删除中间数字。 But it must use the function free() . 但是它必须使用free()函数。

Right now,I have created the list (1,2,3) by using linked list method. 现在,我已经使用链接列表方法创建了列表(1,2,3) I want to delete the number 2 but it doesn't work. 我想删除数字2,但不起作用。 It should be comes out with (1,3) but it comes out with (2,3) . 它应该与(1,3)但它与(2,3)

#include <stdio.h>
#include <stdlib.h>


struct node{
    int number;
    struct node* next;
};

typedef struct node node;

//prototype function
node* allocateMemory(void);
node* insertNode(node*);
void delnode(node*);

int main(){
    int i,num;
    node* entr = allocateMemory();
    node* p = NULL;

    entr->number = 1;
    entr->next = NULL;

    num = 3;

    for(i=1;i<num;i++){
        if(!p){
            p=insertNode(entr);
        }else{
            p=insertNode(p);
        }

        p->number = i+1;
    }

    while(entr){
        if(entr->number == 2){
            entr->number == NULL;
            break;
        }
        entr=entr->next;
    }

    while(entr){
        printf("%d\n",entr->number);
        entr=entr->next;
    }

    return 0;
}

node* insertNode(node* current){
    node* newNode = allocateMemory();
    current->next = newNode;
    newNode->next = NULL;
    return newNode;
}


void delnode(node* current){
    node* temp = allocateMemory();
    temp = current->next->next;
    free(current->next);
    current = temp;
    free(temp);
    return ;
}

node* allocateMemory(void){
    return (node*)malloc(sizeof(node));
}

Some issues: 一些问题:

(1) The original list you are creating is [2,3], and not [1,2,3] - your loop iterates for i=1,i=2 - and in each you insert i+1 - resulting in [2,3] (1)您要创建的原始列表是[2,3],而不是[1,2,3]-循环迭代i = 1,i = 2-并在每个循环中插入i + 1-导致[ 2,3]
(2) Your deletion is not doing anything: (2)您的删除操作无效:

while(entr){
   if(entr->number == 2){
       entr->number == NULL;
       break;
   }
   entr=entr->next;
}

Note that entr->number == NULL is only a boolean evaluation and not an assignment - since you use operator== 请注意, entr->number == NULL只是布尔值评估,而不是赋值-因为您使用operator==

(Note it would fail for operator= as well, because you do not want to assign NULL to the value - what you really want to do is assign the previous node next field.) (请注意,对于operator=也会失败,因为您不想将NULL分配给该值-您真正想要做的就是将前一个节点分配给next字段。)

PS 聚苯乙烯
The terminology for this data structure is a Linked List , not a "Linear List" 此数据结构的术语是链接列表 ,而不是“线性列表”

Ok, this function delnode is all kinds of messed up. 好的,该函数delnode各种各样。 You don't need to allocate more memory when you're trying to delete a node. 尝试删除节点时,不需要分配更多的内存。 You need to link the previous to the next, and delete the current . 您需要将前一个链接到下一个,然后删除当前的

| prev |      | current |      | next |
|------|      |---------|      |------|
   /\              X               /\
   ||              X               ||
   |================================|

It should look more like this. 它看起来应该更像这样。

void delnode(node* current)
{
  node* next = current->next;
  // Now we need to find the node previous to this.
  node* prev = entr; // From the start.
  while(prev->next != current) { prev = prev->next; };
  free(current); // delete the current node.
  prev->next = next; // Link the previous node to the next in the list.
}

If you're trying to add three nodes, you need to change your loop. 如果要添加三个节点,则需要更改循环。

node* current = entr;
for(i=0;i<3;i++)
{
  int newCount = current->number++; // Increment count.
  current = insertNode(current); // Returns the new node.
  current->number = newCount; // Assign new count.
}

If you want to delete the node with number of 2 : 如果要删除number2的节点:

node* idx = entr;
while(idx)
{
  if(idx->number == 2) { delnode(idx); break; } // Delete node and break.
  idx = idx->next; // Else, go to next node.
}

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