我的 cout 有什么问题？

Question

In C++, Ubunt 12.04, I have a file named config.txt which contains user name and password . I have 2 public static string variables: USER and PASSWORD . This is my code:

// Read file from config
string text[2];
int count = 0;
while(!fin.eof()){
    getline(fin,text[count]);
    count++;
    if(count == 2){
        break;
    }
}
CONNECTOR::USER = text[0];
CONNECTOR::PASSWORD = text[1];

string userAndPassword =  CONNECTOR::USER + ":" + CONNECTOR::PASSWORD;
cout << CONNECTOR::USER << endl; // It's fine, right user: qsleader
cout << CONNECTOR::PASSWORD << endl; // ok, right password: 123456
cout <<"user and password: " <<  userAndPassword << endl; // It's weird text! Problem here!

The weird text result is: :123456d password: qsleader !! This is not what I expected! But I don't know why this happen? Can anyone give me an suggestion? (If i print: cout << "user and password: qsleader:123456" , the result is good!!)!

Answer 1

The problem is created when you read the values. Indeed, I guess that your file has the two items on two different lines. Furthermore, I guess this file uses Windows line endings. Therefore, when you read the first item, it reads qsleader\\r and then stops as the next extracted character is \\n , extracted but not appended to the string.

When you create the userAndPassword string, it is in fact qsleader\\r:123456 . This special character \\r is a return carriage. It makes the cursor go to the beginning of the line. Therefore, on the last line, you first output user and password: qsleader , then go back to the first column, and write :123456 , resulting in :123456d password: qsleader .

Answer 2

You are setting userAndPassword to a hellish expression involving assignments. I guess your intent was:

string userAndPassword = CONNECTOR::USER + ":" + CONNECTOR::PASSWORD