带单选按钮的jQuery post函数

Question

In my Django app, I would like to use Twitter bootstrap radio buttons. Then I would like to post the value of those buttons in order to create an object.

Here is my buttons:

  <div class="btn-group" data-toggle="buttons-checkbox">
  <button type="button" class="btn" name="supporting">Team1</button>
  <button type="button" class="btn" name="supporting">Team2</button>
  </div>


  <div class="span6 btn-group ib" data-toggle="buttons-radio">
       <button type="button" class="btn btn-primary active" name="style">relaxed</button>
       <button type="button" class="btn btn-primary active" name="style">strict</button>
  </div>



  <input type="submit" value="create your match">

I would like to get the information from those radio button and create an object match with it in a view:

   def test(request):
       user=request.user
       if request.method == 'POST':
       style = request.POST['style']
       supporting = request.POST['supporting']
       match = Match.objects.create(user=user, style=style, supporting=supporting)
     return HttpResponse(test)

The thing is that I don't know JavaScript well, so I didn't find how to get the value from the button.

Then, I think I have to use:

 $.post('/sportdub/points_dub/', {'style': style , 'supporting': supporting});

But how can I do so that style and supporting correspond to the value of the buttons, and then to post it only when the user clicks on the button?

Thank you very much for your help.

Answer 1

taking my last answer , let's use your own code... in your HTML you have something like:

<form action="/sportdub/points_dub/" method="post" class="form-horizontal">

  <div class="btn-group" data-toggle="buttons-checkbox">
    <button type="button" class="btn" name="supporting">Team1</button>
    <button type="button" class="btn" name="supporting">Team2</button>
  </div>

  <div class="span6 btn-group ib" data-toggle="buttons-radio">
    <button type="button" class="btn btn-primary active" name="style">relaxed</button>
    <button type="button" class="btn btn-primary active" name="style">strict</button>
  </div>

  <input type="submit" value="create your match" />

</form>

and you just have to add one hidden field per block, in your case, add 2. Your form would then match:

<form action="/page" method="post" class="form-horizontal">

  <input type="hidden" id="supporting_team" value="" />
  <input type="hidden" id="supporting_type" value="" />

  <div class="btn-group supporting_team" data-toggle="buttons-checkbox">
    <button type="button" class="btn" name="supporting">Team1</button>
    <button type="button" class="btn" name="supporting">Team2</button>
  </div>

  <div class="span6 btn-group ib supporting_type" data-toggle="buttons-radio">
    <button type="button" class="btn btn-primary active" name="style">relaxed</button>
    <button type="button" class="btn btn-primary active" name="style">strict</button>
  </div>

  <input type="submit" value="create your match" />

</form>

add a jQuery helper that will set the values of those hidden fields upon buttons click:

// whenever a button is clicked, set the hidden helper
$(".supporting_team .btn").click(function() {
    $("#supporting_type").val($(this).text());
}); 
$(".supporting_type .btn").click(function() {
    $("#supporting_team").val($(this).text());
}); 

when you click the create your match the entire form will be posted to the page set as the action attribute of the form, you have to do nothing more...

If you want to submit it manually by invoking post in javascript you need to remember to prevent the form to be submitted again as that's the input type="submit" element task, you can invoke your post and serializing the entire form data, instead one by one as in your example...

like:

// when the form is submited...
$("form").submit(function() {

   // submit it using `post`
   $.post('/sportdub/points_dub/', $("form").serialize()); 

   // prevent the form to actually follow it's own action
   return false; 

});

in your dynamic code, you will have those variables as:

supportingTeam = request.POST['supporting_team']
supportingType = request.POST['supporting_type']

and this, will be valid, no matter if you have the manually form submit script or not...

Answer 2

After your most recent comment, I think you should try using the input radio buttons provided in HTML. It is very easy to do button groupings, make labels for the inputs, and retrieve which one has been clicked.

Altering your HTML slightly to look like this (the for attribute of the label allows the user to be able to click the label and select the radio button instead of clicking on the button directly):

  <div>
    <input id="team1" type="radio" name="supporting" value="Team1" /><label for="team1">Team 1</label>
    <input id="team2" type="radio" name="supporting" value="Team2" /><label for="team2">Team 2</label>
  </div>
  <div>
    <input id="relaxed" type="radio" name="style" value="relaxed" /><label for="relaxed">Relaxed</label>
    <input id="strict" type="radio" name="style" value="strict" /><label for="strict">Strict</label>
  </div>

I can get which selections have been made using this:

$('input[name="supporting"]').filter(':checked').val();
$('input[name="style"]').filter(':checked').val();

If you still wish to use buttons, class active is added to a radio button when clicked. To get the button text, try:

$('button[name="supporing"]').filter('.active').text();
$('button[name="style"]').filter('.active').text();

To put this value into a hidden input, do the following:

$('#hiddenInput1').val($('button[name="supporting"]').filter('.active').text());
$('#hiddenInput2').val($('button[name="style"]').filter('.active').text());