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函数返回指向结构的指针

[英]Function returning pointer to struct

I am having some issues with code that is returning a pointer to a struct declared inside a class.我在返回指向在类中声明的结构的指针的代码有一些问题。 Here is my code so far:到目前为止,这是我的代码:

SortedList.h排序列表.h

#ifndef SORTEDLIST_H
#define SORTEDLIST_H

class SortedList{

 public:

    SortedList();

 ...

 private:

    struct Listnode {    

      Student *student;

      Listnode *next;

    };

    static Listnode *copyList (Listnode *L);

};

#endif

SortedList.cpp排序列表.cpp

#include "SortedList.h"

...

// Here is where the problem lies

Listnode SortedList::*copyList(Listnode *L)

{

    return 0; // for NULL

}

Apparently, the copy list method wont compile.显然,复制列表方法不会编译。 I am using Microsoft Visual Studio and the compiler tells me that "Listnode" is unidentified.我正在使用 Microsoft Visual Studio 并且编译器告诉我“Listnode”未识别。 When I try to compile, here is whhat I get:当我尝试编译时,这是我得到的:

1>------ Build started: Project: Program3, Configuration: Debug Win32 ------

1>  SortedList.cpp

sortedlist.cpp(159): error C2657: 'SortedList::*' found at the start of a statement (did you forget to specify a type?) sortedlist.cpp(159):错误 C2657:在语句开头找到“SortedList::*”(您是否忘记指定类型?)

sortedlist.cpp(159): error C4430: missing type specifier - int assumed. sortedlist.cpp(159):错误 C4430:缺少类型说明符 - 假设为 int。 Note: C++ does not support default-int注意:C++ 不支持 default-int

sortedlist.cpp(159): error C2065: 'L' : undeclared identifier sortedlist.cpp(159):错误 C2065:“L”:未声明的标识符

sortedlist.cpp(159): error C4430: missing type specifier - int assumed. sortedlist.cpp(159):错误 C4430:缺少类型说明符 - 假设为 int。 Note: C++ does not support default-int注意:C++ 不支持 default-int

sortedlist.cpp(159): fatal error C1903: unable to recover from previous error(s); sortedlist.cpp(159):致命错误 C1903:无法从之前的错误中恢复; stopping compilation停止编译

========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

Help would be greatly appreciated...ASAP帮助将不胜感激...尽快

Inside the cpp file, the function should be defined as:在 cpp 文件中,该函数应定义为:

SortedList::Listnode* SortedList::copyList(ListNode* L)
{
    return 0; //For NULL
}

Also, the struct Listnode should be declared either public or outside the class SortedList .此外, struct Listnode应声明为public或在class SortedList之外声明。

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