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SQL每小时​​数据

[英]SQL Hourly Data

The query below retrieves weather data from a MySql database, and groups this data in to an hourly format. 下面的查询从MySql数据库中检索天气数据,并将此数据分组为每小时格式。

select hour(datetime) AS hour
     , avg(Temperature) as AVGT 
from Database.minute
WHERE DATETIME
      BETWEEN (CURDATE() + INTERVAL (SELECT hour(NOW())) hour - INTERVAL 23 hour)
         AND ((CURDATE() + INTERVAL (SELECT hour(NOW())) hour))
group by hour
order by  (CURDATE() + INTERVAL (SELECT hour(NOW())) hour - INTERVAL 23 hour)

Output is as follows: 输出如下:

hour    AVGT
19     11.730
20     11.970
21     11.970
22     11.760
23     11.660
0      11.700
1      11.830
2      12.370
3      12.770
4      12.840
5      12.840
6      12.540
7      12.500
8      12.030
9      12.100
10     12.300
11     12.060
12     11.090
13     10.920
14     10.920
15     10.820
16     10.760
17     10.690
18     10.560

The time is now 18:15. 现在时间是18:15。 All of the above output is correct apart from the data gathered for hour '18'. 除了为'18'小时收集的数据之外,所有上述输出都是正确的。 Instead of getting the average value between 18:00 and 18:15, it just outputs the average at time 18:00. 它不是在18:00到18:15之间获得平均值,而是在18:00时输出平均值。 ie. 即。 ignoring data between 18:01 and 18:14. 在18:01和18:14之间忽略数据。

How can I modify the above query to include data in the current hour (18:00 to Now)? 如何修改上述查询以包含当前小时(18:00到现在)的数据?

Thanks 谢谢

Why don't you simply try 你为什么不试试呢?

SELECT Hour(datetime)   AS hour, 
       Avg(temperature) AS AVGT 
FROM   DATABASE.minute 
WHERE  datetime BETWEEN ( Curdate() + INTERVAL (SELECT Hour(Now())) hour - 
                          INTERVAL 23 hour ) AND Now() 
GROUP  BY hour 
ORDER  BY ( Curdate() + INTERVAL (SELECT Hour(Now())) hour - INTERVAL 23 hour ) 

I agree with @Ankur's answer (your filter citerion should not filter records up to the current hour, but rather the current time), however your date/time operations are very strange: 我同意@ Ankur的回答 (你的过滤器citerion不应该过滤记录到当前时间,而是当前时间),但是你的日期/时间操作非常奇怪:

  1. You don't need a subquery (SELECT Hour(NOW())) to obtain HOUR(NOW()) ; 你不需要子查询(SELECT Hour(NOW()))来获得HOUR(NOW()) ;

  2. You can express ( Curdate() + INTERVAL (SELECT Hour(NOW())) hour - INTERVAL 23 hour ) more simply: 您可以更简单地表达( Curdate() + INTERVAL (SELECT Hour(NOW())) hour - INTERVAL 23 hour )

     CURDATE() + INTERVAL HOUR(NOW()) - 23 HOUR 

    Or, in my view, more clearly: 或者,在我看来,更清楚:

     DATE_FORMAT(NOW() - INTERVAL 23 HOUR, '%Y-%m-%d %H:00:00') 
  3. Your ORDER BY clause is a constant and therefore achieves nothing: did you mean to order by hour ? 你的ORDER BY子句是一个常数,因此没有任何结果:你的意思是按hour排序吗?

Therefore: 因此:

SELECT   HOUR(datetime) AS hour,
         AVG(Temperature) AS AVGT
FROM     Database.minute
WHERE    datetime BETWEEN
               DATE_FORMAT(NOW() - INTERVAL 23 HOUR, '%Y-%m-%d %H:00:00')
           AND NOW()
GROUP BY hour
ORDER BY hour

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