如何打印某些内容然后列出其中的内容？

Question

I've got a txt file of all the countries in the world and what kind of products do they export.

This is what one line looks like without any splitting or stripping (notice \\t and \\n ): [Jamaica\\t alumina, bauxite, sugar, rum, coffee, yams, beverages, chemicals, wearing apparel, mineral fuels\\n]

I have to write a program which does that:

Angola
[ 'oil,', 'diamonds,', 'refined', 'petroleum', 'products,', 'coffee,', 'sisal,', 'fish,', 'fish', 'products,', 'timber,', 'cotton']

Anguilla
[ 'lobster,', 'fish,', 'livestock,', 'salt,', 'concrete', 'blocks,', 'rum']

Antigua and Barbuda
[ 'petroleum', 'products,', 'bedding,', 'handicrafts,', 'electronic', 'components,', 'transport', 'equipment,', 'food,', 'live', 'animals']

Argentina
[ 'soybeans,', 'petroleum,', 'gas,', 'vehicles,', 'corn,', 'wheat']

This is what I've done so far but from now on I don't know how to go forward:

import os
file=open("exports.txt",'r')
list=[]

for i in file:
    list.append(i.split(" "))

for i in range(len(list)):
    print(list[i])

As a result I get a list of every country and what does it export:

['Angola\t', 'oil,', 'diamonds,', 'refined', 'petroleum', 'products,', 'coffee,', 'sisal,', 'fish,', 'fish', 'products,', 'timber,', 'cotton\n']
['Anguilla\t', 'lobster,', 'fish,', 'livestock,', 'salt,', 'concrete', 'blocks,', 'rum\n']
['Antigua', 'and', 'Barbuda\t', 'petroleum', 'products,', 'bedding,', 'handicrafts,', 'electronic', 'components,', 'transport', 'equipment,', 'food,', 'live', 'animals\n']
['Argentina\t', 'soybeans,', 'petroleum,', 'gas,', 'vehicles,', 'corn,', 'wheat\n']

How do I countinue? Thanks for help

Answer 1

This should do it

with open("exports.txt",'r') as infile:
    exports = {}
    for line in infile:
        parts = line.partition('\t')
        exports[parts[0]] = parts[-1].strip().split(', ')

for country, exports in exports.iteritems():
    print country
    print exports

Hope this helps

Answer 2

Assuming you have already got the list you mentioned, you can simply do

>>> some_list
[['Angola\t', 'oil,', 'diamonds,', 'refined', 'petroleum', 'products,', 'coffee,', 'sisal,', 'fish,', 'fish', 'products,', 'timber,', 'cotton\n'], ['Anguilla\t', 'lobster,', 'fish,', 'livestock,', 'salt,', 'concrete', 'blocks,', 'rum\n'], ['Antigua', 'and', 'Barbuda\t', 'petroleum', 'products,', 'bedding,', 'handicrafts,', 'electronic', 'components,', 'transport', 'equipment,', 'food,', 'live', 'animals\n'], ['Argentina\t', 'soybeans,', 'petroleum,', 'gas,', 'vehicles,', 'corn,', 'wheat\n']]
>>> for row in some_list:
    print row[0]
    print map(str.strip,row[1:])


Angola  
['oil,', 'diamonds,', 'refined', 'petroleum', 'products,', 'coffee,', 'sisal,', 'fish,', 'fish', 'products,', 'timber,', 'cotton\n']
Anguilla    
['lobster,', 'fish,', 'livestock,', 'salt,', 'concrete', 'blocks,', 'rum\n']
Antigua
['and', 'Barbuda\t', 'petroleum', 'products,', 'bedding,', 'handicrafts,', 'electronic', 'components,', 'transport', 'equipment,', 'food,', 'live', 'animals\n']
Argentina   
['soybeans,', 'petroleum,', 'gas,', 'vehicles,', 'corn,', 'wheat\n']
>>> 

Answer 3

When you're iterating through the list from the file, you can use list.pop(0) - this will give you the first element of the list and remove it from the list.

I'd also recommend switching to using the with keyword for opening the file, and changing your variable name. So something like:

with open("exports.txt",'r') as infile:
    lines = infile.readlines()

for line in lines: 
    print line.pop(0) #Note that this doesn't actually remove the tab
    print line

Answer 4

My advice: construct a dict mapping the country to the things it produces, and split each line on the "\\t"

file=open("exports.txt",'r')
dict = {}

for i in file:
    spl_line = i.split("\t")
    dict[spl_line[0]] = spl_line[1].split(" ")