[英]Passing variable to regular expression
I have a regular expression 我有一个正则表达式
var p = /\bj[^\b]*?\b/gi;
I need to make the 'j' a variable value, but when i do the following;- 我需要将'j'设为变量值,但是当我执行以下操作时:-
var p = new RegExp('\\b'+'${0}'+'[^\\b]*?\\b', 'gi');
I get error - 我收到错误-
Uncaught SyntaxError: Invalid regular expression: /\b${0}[^\b]*?\b/: Nothing to repeat
Any help appreciated. 任何帮助表示赞赏。
Thank you 谢谢
I think you want the following: 我认为您需要以下条件:
var p = new RegExp('\\b'+${0}+'[^\\b]*?\\b', 'gi');
With the quotes around ${0}
you are just constructing a string with those characters, instead of inserting the variable value. 使用
${0}
前后的引号,您仅用这些字符构造一个字符串,而不是插入变量值。
Putting a variable within quotation marks as you have done with '${0}'
is going to cause that to be treated as a string. 与
'${0}'
所做的操作一样,将变量放在引号内将导致该变量被视为字符串。 If you remove the quotation marks from around it then it will be treated as a variable. 如果删除引号周围的引号,则它将被视为变量。
Sorry guys, I should have been more clear, the value '{0}' is a token that will be replaced and not a variable. 抱歉,我应该更加清楚,值'{0}'是将被替换的令牌,而不是变量。 The error was occurring because '{' and '}' are special characters in regular expressions.
发生错误是因为'{'和'}'是正则表达式中的特殊字符。
So changing the token pattern fixed the problem 因此,更改令牌模式可以解决问题
var p = new RegExp('\\b'+'%text%'+'[^\\b]*?\\b', 'gi');
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