[英]Convert vector<string> * char to int
I need help in my following code and hope that you can help me through. 我需要以下代码中的帮助,希望您能帮助我完成。 All I wanted is to pass in INT type to setX() and setY().
我想要的只是将INT类型传递给setX()和setY()。 However, there is no way for me to convert vector char* to int.
但是,我无法将vector char *转换为int。 Is there alternative to this?
有替代品吗?
template<class T>
vector<string> Delimiter(T inputString){
int count=0;
char str[inputString.length()];
strcpy(str,inputString.c_str());
char * pch;
vector<string> returnContainer;
printf ("Splitting string \"%s\" into tokens:\n",str);
pch = strtok (str,",[]");
while (pch != NULL)
{
returnContainer.push_back(pch);
pch = strtok (NULL, " ,[]");
count++;
}
for(int i=0; i<returnContainer.size(); i++){
cout << "return:" << returnContainer[i] << endl;
}
return returnContainer;
}
//Main() //主要()
fileDataAfterFiltered = Delimiter(fileData[i]); // Delimiter (vector<string> type)
point2DObj[point2DCount].setX(fileDataAfterFiltered[1]); // error
point2DObj[point2DCount].setY(fileDataAfterFiltered[2]); // error
//Assn3.cpp:107:59: error: no matching function for call to 'Point2D::setX(std::basic_string&)' //Assn3.cpp:107:59:错误:没有匹配函数来调用'Point2D :: setX(std :: basic_string&)'
there's plenty of ways of converting string to int. 有很多方法可以将字符串转换为int。 boost::lexical_cast is one which will magically do the conversion you want.
boost :: lexical_cast是一个神奇地进行你想要的转换的人。 Otherwise you can use atoi (if you don't care about errors), or strtol (if you do).
否则你可以使用atoi(如果你不关心错误),或strtol(如果你这样做)。
point2DObj[point2DCount].setX(atoi(fileDataAfterFiltered[1].c_str()));
point2DObj[point2DCount].setX(boost::lexical_cast<int>(fileDataAfterFiltered[1]));
Delimiter()
returns a vector<string>
and you give one of these strings to setX()
and setY()
, but both expect an integer parameter. Delimiter()
返回一个vector<string>
,你将其中一个字符串setY()
setX()
和setY()
,但两者都需要一个整数参数。 You must convert the string to int 您必须将字符串转换为int
int x = atoi(fileDataAfterFiltered[1].c_str());
point2DObj[point2DCount].setX(x);
int y = atoi(fileDataAfterFiltered[2].c_str());
point2DObj[point2DCount].setY(y);
But : in C++ array and vector elements start at 0 not 1, so you might want to replace this with fileDataAfterFiltered[0]
and fileDataAfterFiltered[1]
respectively. 但是 :在C ++数组中,向量元素从0开始而不是 1,因此您可能希望分别用
fileDataAfterFiltered[0]
和fileDataAfterFiltered[1]
替换它。
If you are using a C++11 compiler, function std::stoi()
will do the trick: 如果您使用的是C ++ 11编译器,函数
std::stoi()
将起到作用:
point2DObj[point2DCount].setX(std::stoi(fileDataAfterFiltered[1]));
Otherwise you can use the old atoi()
: 否则你可以使用旧的
atoi()
:
point2DObj[point2DCount].setX(atoi(fileDataAfterFiltered[1].c_str()));
Aside from this, your code has many other problems, but I hope you can fix them by yourself. 除此之外,您的代码还有许多其他问题,但我希望您可以自己修复它们。
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