[英]Missing ; before 'type' error
This is part of my code, do you know what causes this missing ; 这是我的代码的一部分,您知道导致这种丢失的原因吗? before 'type' error? 在“类型”错误之前? It disappears when I delete sort(arr, size) in the main() function... 当我在main()函数中删除sort(arr,size)时,它消失了...
#include <stdio.h>
void sort(int*, int);
int main() {
int arr[] = {5, 1, 3, 0, 9};
int size = sizeof(arr) / sizeof(arr[0]);
sort(arr, size);
int i;
for(i = 0; i < size; i++)
printf("%d", arr[i]);
getchar();
return 0;
}
void sort(int *array, int size) {
// ...
}
You are most likely using a compiler that is strictly C89 and thus does not allow you to define a variable after non-definition code in the same block. 您最有可能使用严格为C89的编译器,因此不允许您在同一块中的未定义代码之后定义变量。 Move the int i;
移动int i;
above the sort
call and it should work again: 以上的sort
调用,它应该可以再次工作:
int main() {
int arr[] = {5, 1, 3, 0, 9};
int size = sizeof(arr) / sizeof(arr[0]);
int i;
sort(arr, size);
for(i = 0; i < size; i++)
printf("%d", arr[i]);
getchar();
return 0;
}
Or even better, consider using the C99 standard if your compiler supports it. 甚至更好的是,如果编译器支持,请考虑使用C99标准。 This would even to allow you to inline the int i
, ie like this: for(int i = 0; i < size; i++)
这甚至允许您内联int i
,即像这样: for(int i = 0; i < size; i++)
If you're in proper old school C you can't define a variable after a function call. 如果您使用的是老式C语言,则无法在函数调用后定义变量。
So just do: 所以做:
#include <stdio.h>
void sort(int*, int);
int main() {
int arr[] = {5, 1, 3, 0, 9};
int size = sizeof(arr) / sizeof(arr[0]);
int i;
sort(arr, size);
for(i = 0; i < size; i++)
printf("%d", arr[i]);
getchar();
return 0;
}
void sort(int *array, int size) {
// ...
}
You can't declare variables in midst of the code in pre-C99 C. Move your int i
; 你不能在预C99 C的代码中间声明变量将您的int i
; to the beginning of the block, near rest of variables declarations. 到块的开始,靠近变量声明的其余部分。
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