Python调用与命名参数同名的函数

Question

In a module, I have two functions, let's call them f and g . g takes a named argument f . I'd like to call f from inside g . How do I access the function f ? Unfortunately, due to compatibility issues, I can't change their names.

Edit

To clarify, this is what I mean:

def f():
  ... code ...

def g(f=1):
  ... code ...
  x = f() # error, f doesn't name the function anymore
  ... code ...

Answer 1

You could add a new name for the function.

Eg:

def f():
    pass

f_alt = f

def g(f=3):
    f_alt()

Just don't export f_alt from the module.

Answer 2

Basic example using globals :

def f():
    print 'f'

def g(name):
    globals()[name]()

g('f')

Answer 3

Though globals() seems like a simple solution here, you can also achieve the same thing by defining a inner function inside g() that calls the global f :

def f():print "hello"

def g(f):
    def call_global_f():
        global f
        f()
    call_global_f()      #calls the global f
    print f              #prints the local f

g('foo')

output:

hello
foo