[英]send many NSURLConnection requests and get response in connectionDidFinishLoading
I'm trying to send many asynchronous request to php file that shows my data as json code and in the response I parse the json so I added the following in ViewDidload: 我正在尝试向php文件发送许多异步请求,将我的数据显示为json代码,并在响应中解析json,因此我在ViewDidload中添加了以下内容:
NSURLRequest *aboutRequest = [self getDataFromServer:@"http://al-awal.com/Rashad/iPhonePhp/about.php"];
aboutConn = [[NSURLConnection alloc] initWithRequest:aboutRequest delegate:self];
NSURLRequest *wisdomRequest = [self getDataFromServer:@"http://al-awal.com/Rashad/iPhonePhp/wisdomtoday.php"];
wisdomConn = [[NSURLConnection alloc] initWithRequest:wisdomRequest delegate:self];
then 然后
-(NSURLRequest *) getDataFromServer:(NSString *)phpUrl{
responseData = [NSMutableData data];
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:phpUrl]];
return request;
}
then I added: 然后我补充说:
- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
sqlite3 *database;
if(sqlite3_open([[rashadDB databasePath] UTF8String], &database) == SQLITE_OK) {
if (connection == aboutConn) {
NSLog(@"get from table about");
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSString *json_string = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
NSArray *statuses = [parser objectWithString:json_string error:nil];
for (NSDictionary *status in statuses)
{
NSString *sAboutID = [status objectForKey:@"ID"];
NSString *sPhone1 = [status objectForKey:@"Phone1"];
NSString *sPhone2 = [status objectForKey:@"Phone2"];
NSString *sJawal = [status objectForKey:@"Jawal"];
NSString *sFax = [status objectForKey:@"Fax"];
NSString *sWebSite = [status objectForKey:@"WebSite"];
NSString *sEmail = [status objectForKey:@"Email"];
NSString *sAddress = [status objectForKey:@"Address"];
int sAboutID2 = [sAboutID intValue];
NSLog(@"in server, aboutID = %d, Phone1 = %@, Phone2 = %@, Jawal = %@, Fax = %@, WebSite = %@, Email = %@, Address = %@",sAboutID2, sPhone1, sPhone2, sJawal, sFax, sWebSite, sEmail, sAddress);
sqlite3_exec(database, [[NSString stringWithFormat:@"INSERT OR ABORT INTO About VALUES(%d, '%@', '%@', '%@', '%@', '%@', '%@', '%@')",sAboutID2, sPhone1, sPhone2, sJawal, sFax, sWebSite, sEmail, sAddress] UTF8String], NULL, NULL, NULL);
sqlite3_exec(database, [[NSString stringWithFormat:@"UPDATE About set Phone1 = '%@', Phone2 = '%@', Jawal = '%@', Fax = '%@', WebSite = '%@', Email = '%@', Address = '%@' Where aboutID = %d", sPhone1, sPhone2, sJawal, sFax, sWebSite, sEmail, sAddress, sAboutID2] UTF8String], NULL, NULL, NULL);
}
} else if (connection == wisdomConn) {
NSLog(@"get from table wisdoms");
SBJsonParser *parser = [[SBJsonParser alloc] init];
NSString *json_string = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
NSArray *statuses = [parser objectWithString:json_string error:nil];
for (NSDictionary *status in statuses)
{
NSString *sWisdomTodayID = [status objectForKey:@"ID"];
NSString *sContent = [status objectForKey:@"Content"];
NSString *sAuthorName = [status objectForKey:@"AuthorName"];
NSString *sDateCreate = [status objectForKey:@"DateCreate"];
NSString *sEnable = [status objectForKey:@"Enable"];
int sWisdomTodayID2 = [sWisdomTodayID intValue];
int sEnable2 = [sEnable intValue];
NSLog(@"wisdomTodayID = %@, Content = '%@', AuthorName = '%@', DateCreate = '%@', Enable = %@", sWisdomTodayID, sContent, sAuthorName, sDateCreate, sEnable);
sqlite3_exec(database, [[NSString stringWithFormat:@"INSERT OR ABORT INTO WisdomToday VALUES(%d, '%@', '%@', '%@', %d)",sWisdomTodayID2, sContent, sAuthorName, sDateCreate, sEnable2] UTF8String], NULL, NULL, NULL);
sqlite3_exec(database, [[NSString stringWithFormat:@"UPDATE WisdomToday set Content = '%@', AuthorName = '%@', DateCreate = '%@', Enable = %d Where wisdomTodayID = %d", sContent, sAuthorName, sDateCreate, sEnable2, sWisdomTodayID2] UTF8String], NULL, NULL, NULL);
}
}
} // sqlite3 open end
sqlite3_close(database);
}
the first if condition --> if(connection == aboutConn) works ok with me and I got my output but the other if condition --> if (connection == wisdomConn) only gives me this output NSLog(@"get from table wisdoms"); 第一个if条件 - > if(connection == aboutConn)和我一起正常工作我得到了我的输出但是另一个条件 - > if(connection == wisdomConn)只给我这个输出NSLog(@“从表中获取智慧“); and not go throw the for loop.
而不是去抛出for循环。 Is there are any wrong in my code?
我的代码有什么问题吗?
You are not closing braces properly... 你没有正确关闭牙箍......
Before opening the brace for else - if condition you should close the brace for if_condition.. 在为else打开括号之前 - 如果条件你应该关闭if_condition的括号..
Some of your relevant code is missing (the NSConnectionDataDelegate
methods). 缺少一些相关代码(
NSConnectionDataDelegate
方法)。 But it would seem that you are using one instance variable, responseData
, to build up both return values. 但似乎您正在使用一个实例变量
responseData
来构建两个返回值。 This would mean that some times you would get the faster response data only; 这意味着有时候你会得到更快的响应数据; and other times you would get mixed data in the same
NSMutableData
object. 有时你会在同一个
NSMutableData
对象中获得混合数据。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.