如何在 C++ 控制台中删除已写入的字符

Question

I'm trying to make a C++ program to read a password. I made the program to cout * , not the characters I write but my problem is when I want to delete character because they're wrong.
Example: My constant password is 12345
If I enter 1235 the program will show **** and I have to delete the last character. It's simple to remove it from the string but I want the last * to disappear from the console just as it happens when you introduce you windows password.
Is it possible? If it is, can someone explain how?

Answer 1

Outputting the backspace character '\\b' may help to move the output point back.

Specifically, outputting the string "\\b \\b" should blank out the last character output.

Answer 2

printf("\b ");

这句话肯定有效，因为在光标返回一个字符后，上面printf语句中给出的空格将覆盖控制台输出上的打印字符。

Answer 3

When I am writting to console using putch function ( from conio.h ) to simulate backspace key simple

std::cout << '\b';

or

printf("\b ");

not works I have to write:

cout << '\b' << " " << '\b';

or

putch('\b');
putch(' ');
putch('\b');

Answer 4

尝试退格\\ b或删除整行并再次打印。

Answer 5

Sipmly write the '\\b' character to stdout std::cout<<"\\b" . If you are using cpp or printf("\\b") for pure C

Answer 6

I faced the same thing recently, using the \\b was** moving the cursor backward** but it was not deleting the char (or * ). I realize after that the next character you enter after \\b is gonna replace the (character to be deleted). So, I came up with something like this

printf(“\b \b”);

using the space key after \\b will replace the character to be deleted and again using the \\b will take you one position back again (to the position where was incorrect character was, but this time the character will not be there) This way your output will look smooth. hope it will be helpful to you