[英]How to fetch all links and click those links one by one using Selenium WebDriver
I am using Selenium WebDriver with java. 我正在使用Selenium WebDriver和java。
I am fetching all links from webpage and trying to click each link one by one. 我从网页上获取所有链接,并尝试逐个点击每个链接。 I am getting below error: 我收到以下错误:
error org.openqa.selenium.StaleElementReferenceException: Element not found in the cache - perhaps the page has changed since it was looked up Command duration or timeout: 30.01 seconds For documentation on this error, please visit: http://seleniumhq.org/exceptions/stale_element_reference.html Build info: version: '2.25.0', revision: '17482', time: '2012-07-18 21:09:54' 错误org.openqa.selenium.StaleElementReferenceException:在缓存中找不到元素 - 自查询以来页面可能已更改命令持续时间或超时:30.01秒有关此错误的文档,请访问: http : //seleniumhq.org/ exceptions / stale_element_reference.html构建信息:版本:'2.25.0',修订版:'17482',时间:'2012-07-18 21:09:54'
and here is my code : 这是我的代码:
public void getLinks()throws Exception{
try {
List<WebElement> links = driver.findElements(By.tagName("a"));
int linkcount = links.size();
System.out.println(links.size());
for (WebElement myElement : links){
String link = myElement.getText();
System.out.println(link);
System.out.println(myElement);
if (link !=""){
myElement.click();
Thread.sleep(2000);
System.out.println("third");
}
//Thread.sleep(5000);
}
}catch (Exception e){
System.out.println("error "+e);
}
}
actually, it's displaying in output 实际上,它在输出中显示
[[FirefoxDriver: firefox on XP (ce0da229-f77b-4fb8-b017-df517845fa78)] -> tag name: a] [[FirefoxDriver:XP上的firefox(ce0da229-f77b-4fb8-b017-df517845fa78)] - >标签名称:a]
as link, I want to eliminate these form result. 作为链接,我想消除这些形式的结果。
There is no such a good idea to have following scenario : 有以下场景没有这么好的主意:
for (WebElement element : webDriver.findElements(locator.getBy())){
element.click();
}
Why? 为什么? Because there is no guarantee that the element.click();
因为无法保证element.click();
will have no effect on other found elements, so the DOM
may be changed, so hence the StaleElementReferenceException
. 对其他找到的元素没有影响,因此DOM
可能会被更改,因此StaleElementReferenceException
也是StaleElementReferenceException
。
It is better to use the following scenario : 最好使用以下方案:
int numberOfElementsFound = getNumberOfElementsFound(locator);
for (int pos = 0; pos < numberOfElementsFound; pos++) {
getElementWithIndex(locator, pos).click();
}
This is better because you will always take the WebElement
refreshed, even the previous click had some effects on it. 这样更好,因为您将始终刷新WebElement
,即使之前的点击也会对其产生一些影响。
EDIT : Example added 编辑:添加示例
public int getNumberOfElementsFound(By by) {
return webDriver.findElements(by).size();
}
public WebElement getElementWithIndex(By by, int pos) {
return webDriver.findElements(by).get(pos);
}
Hope to be enough. 希望足够。
Credit goes to "loan". 信用归于“贷款”。
I am also getting "stale exception" so I used 'loan' answer and works perfectly. 我也得到“陈旧的例外”所以我使用'贷款'答案并且完美地工作。 Just if anyone need to know how to click on each link from results page try this (java) 如果有人需要知道如何从结果页面点击每个链接试试这个(java)
clickAllHyperLinksByTagName("h3");
where "h3" tag contains hyperlink 其中“h3”标签包含超链接
public static void clickAllHyperLinksByTagName(String tagName){
int numberOfElementsFound = getNumberOfElementsFound(By.tagName(tagName));
System.out.println(numberOfElementsFound);
for (int pos = 0; pos < numberOfElementsFound; pos++) {
getElementWithIndex(By.tagName(tagName), pos).click();
driver.navigate().back();
}
}
public static int getNumberOfElementsFound(By by) {
return driver.findElements(by).size();
}
public static WebElement getElementWithIndex(By by, int pos) {
return driver.findElements(by).get(pos);
}
WebDriver _driver = new InternetExplorerDriver();
_driver.navigate().to("http://www.google.co.in/");
List <WebElement> alllinks = _driver.findElements(By.tagName("a"));
for(int i=0;i<alllinks.size();i++)
System.out.println(alllinks.get(i).getText());
for(int i=0;i<alllinks.size();i++){
alllinks.get(i).click();
_driver.navigate().back();
}
If you're OK using WebDriver.get()
instead of WebElement.click()
to test the links, an alternate approach is to save the href
value of each found WebElement
in a separate list. 如果您可以使用WebDriver.get()
而不是WebElement.click()
来测试链接,则另一种方法是将每个找到的WebElement
的href
值保存在单独的列表中。 This way you avoid the StaleElementReferenceException
because you're not trying to reuse subsequent WebElement
s after navigating away with the first WebElement.click()
. 这样就可以避免StaleElementReferenceException
因为在使用第一个WebElement.click()
导航之后,您不会尝试重用后续的WebElement
。
Basic example: 基本示例:
List<String> hrefs = new ArrayList<String>();
List<WebElement> anchors = driver.findElements(By.tagName("a"));
for ( WebElement anchor : anchors ) {
hrefs.add(anchor.getAttribute("href"));
}
for ( String href : hrefs ) {
driver.get(href);
}
//extract the link texts of each link element
for (WebElement elements : linkElements) {
linkTexts[i] = elements.getText();
i++;
}
//test each link
for (String t : linkTexts) {
driver.findElement(By.linkText(t)).click();
if (driver.getTitle().equals(notWorkingUrlTitle )) {
System.out.println("\"" + t + "\""
+ " is not working.");
} else {
System.out.println("\"" + t + "\""
+ " is working.");
}
driver.navigate().back();
}
driver.quit();
}
List <WebElement> links = driver.findElements(By.tagName("a"));
int linkCount=links.size();
System.out.println("Total number of page on the webpage:"+ linkCount);
String[] texts=new String[linkCount];
int t=0;
for (WebElement text:links){
texts[t]=text.getText();//extract text from link and put in Array
//System.out.println(texts[t]);
t++;
}
for (String clicks:texts) {
driver.findElement(By.linkText(clicks)).click();
if (driver.getTitle().equals("notWorkingUrlTitle" )) {
System.out.println("\"" + t + "\""
+ " is not working.");
} else {
System.out.println("\"" + t + "\""
+ " is working.");
}
driver.navigate().back();
}
driver.quit();
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