如何在此 bash 脚本中使用变量作为变量名

Question

I am currently trying to make a variable name that would consist of another variable

while [ "$countf" -le 9 ]; do
                    vname=$( echo fcp"$countf" )
                    $vname=$( awk -F, -vs="\$fc$countf" '{for (i=1;i<=NF;i++)if($i~"^"s"$"){print i;exit;}}{print "not found"}' <<< $first_line )
                    countf=$(( countf + 1 ))
            done

although when I go to execute the the script that includes the code, something along the lines of the following is outputted:

fcp1=not: command not found

fcp1 being the content of the vname variable. I've tried several different solutions but have not gotten anything to work yet as of right now, if someone could point out what I am doing wrong though I would really appreciate it, thanks.

Answer 1

try this:

eval cat$p2="something"

without the quotes around the variable name.