SQL Select 语句中的 IFF 语句

Question

I am trying to write an IF statement which will perform the following.....

Here is an example of the results in the table....

Name        Exd Name                 RESULT
 HMAA  USA       USA                  HMAA USA
 HMIT  ITL       ITL                  HMIT ITL
 HMTT   LOG       HYT                HMTT LOG (HYT)
 LTYS   LTT      FYM                  LTYS LTT (FYM)
 TTTT   FFF      PPP                 TTTT FFF (PPP)
 FDSE   FGR      FGR                 FDSE FGR

The results should be displayed as follows

HMTT LOG (HYT) -----as the two names are different I wan to display the Exd NAme in brackets), however when HMAA USA , and the Exd Name is also USA - I only want to display the 'Name', not the Exd Name.

Is this possible in a IF statement....This is my script, as you can see it has the name + Exd Name, however above I would like to incorporate an IIF statement in here to only display as per the above logic.

SELECT  distinct  RNL.EmplID,
RNL.ServiceType, rnl.[name] + ' ' + '(' + rnl.[Exd Name] + ')' as 'Vessel'
FROM
resultsIB RNL (nolock)

Answer 1

If it's SQL Server you can try:

select distinct RNL.EmplID, RNL.ServiceType, 
    rnl.[name] + 
    case 
        when rnl.[name] like '%' + rnl.[Exd Name]
        then ''
        else ' (' + rnl.[Exd Name] + ')'
    end as 'Vessel'
FROM resultsIB RNL (nolock)

or using iif (SQL Server 2012 only AFAIK) ( IIF is a shorthand way for writing a CASE ):

select distinct RNL.EmplID, RNL.ServiceType, 
    rnl.[name] + 
    iif(rnl.[name] like '%' + rnl.[Exd Name], '', ' (' + rnl.[Exd Name] + ')') as 'Vessel'
FROM resultsIB RNL (nolock)

Answer 2

SELECT distinct  RNL.EmplID, RNL.ServiceType,
       CASE WHEN CHARINDEX(ExdName, Name) = 0
            THEN Name + ' (' + ExdName + ')'
            ELSE Name END AS 'Vessel'
FROM resultsIB RNL (nolock)