如果我调用此方法，那么我将收到一个错误消息，即“数据库已锁定”。我该如何解决呢？ 请帮我

Question

If I call -(void)insertDataIntoAssemblyAssessment method,where finalAssembIdArr is an array in which must be more than one value, then i'm getting a error which is " database is lock ". But, if in finalAssembIdArr have just one value,then,value are stored in database successfully.

How I can solve this?? Please help me.

-(void)insertDataIntoAssemblyAssessment
{
    sqlite3_stmt *fstatement;
    const char *dbpath = [databasePath UTF8String];
    for(int cnt=0; cnt < [finalAssembIdArr count]; cnt++)
    {
        finalAsmbId2=[finalAssembIdArr objectAtIndex:cnt];

        NSLog(@"finalAsmbId2...%@",finalAsmbId2);
        NSLog(@"finalAssessmentIdSt2...%@",finalAssessmentIdSt2);
        NSLog(@"finalFacIdSt2...%@",finalFacIdSt2);
        NSLog(@"finalSpaceIdSt2...%@",finalSpaceIdSt2);

        if (sqlite3_open(dbpath, &ipadSites) == SQLITE_OK)
        {
            NSLog(@"db opened for AssemblyAssessment..");

            NSString *insertfSQL = [NSString stringWithFormat:@"INSERT INTO AssemblyAssessment (assessmentid,spaceid,assemblyid,FacilityID) VALUES (\"%@\",\"%@\",\"%@\",\"%@\")",self.finalAssessmentIdSt2,self.finalSpaceIdSt2,self.finalAsmbId2,self.finalFacIdSt2];

            NSLog(@"insertfSQL...%@",insertfSQL);


            const char *insert_fstmt = [insertfSQL UTF8String];
                sqlite3_prepare_v2(ipadSites,insert_fstmt,-1,&fstatement,NULL);
                NSLog(@"inserting AssemblyAssessment..");

            if (sqlite3_step(fstatement) == SQLITE_DONE)
            {
                NSLog(@"Add value in AssemblyAssessment...");

            }
            else
            {
                NSLog(@"Insert failed: %s", sqlite3_errmsg(ipadSites));
                NSLog(@"Failed to add value in AssemblyAssessment...");
            } 
        }

        sqlite3_finalize(fstatement);
        sqlite3_close(ipadSites);

    }
}

Answer 1

Please... ! Don't open/close SQLite connection in loop like that! Open handle to database outside from the "FOR loop". Please look here how to insert data into data base in iphone and here How to insert NSMutableArray elements in Sqlite3 in iPhone

And, for the basic CRUD (create, read, update, delete), I suggest you .. to take a look at FMDB

Answer 2

Have you opened the database in SQLite or any other browser ?? If database is opened from outside, it gives same error. Check it. I had same issue.