正则表达式以提取标点符号/字符

Question

Hi guys I need a regex that only extracts punctuations/characters.

I have this so far :

[._^%$#!~@,-]+

but this works if there is at least 1 punctuations and still allows for any other char (digit or letter)

I need to to only allow punctuations/characters

Answer 1

Try this:

^[\p{S}\p{P}]+$

\\p{S} matches any symbol character, and \\p{P} matches any punctuation.

Note that your pattern will not match all the symbols and punctuations not present in the list.

Answer 2

Try anchoring the regex to the start and the end of the string (unless you're using Multiline matching) - ie ^ at the beginning and $ at the end:

^[._^%$#!~@,-]+$

Note - this does not endorse your actual pattern (I can't say whether this is matching all the 'special characters' you're talking about, but it will make it so that the entire string must be all 'special'.

Answer 3

[^a-zA-Z0-9]* u can try something like this. Should NOT accept those chars, cba to writte all beside chars beside one u typed.

Answer 4

\W

匹配不是单词字符的任何字符（字母数字和下划线）。