[英]Simplexml get attributes with a namespace
I have an XML Document which has attributes with a namespace.我有一个具有命名空间属性的 XML 文档。 The XML looks like:
XML 看起来像:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.sunil.tweet"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="11"
android:targetSdkVersion="16" />
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name="com.sunil.tweet.MainActivity"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
How can I extract the android:name
attribute from the activity
tag?如何从
activity
标签中提取android:name
属性?
You need to use the namespace when getting the attribute.获取属性时需要使用命名空间。 The
android
namespace is defined as: android
命名空间定义为:
http://schemas.android.com/apk/res/android
http://schemas.android.com/apk/res/android
So you need to pass that to the attributes()
method, like this:因此,您需要将其传递给
attributes()
方法,如下所示:
$xml = simplexml_load_string($xmlStr);
echo (string) $xml->application->activity->attributes('http://schemas.android.com/apk/res/android')->name;
Outputs输出
com.sunil.tweet.MainActivity
com.sunil.tweet.MainActivity
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