Python函数将所有文件和文件夹移动到目标文件夹

Question

I have a txt file, in which in each line i have the path of files and folders i want to segregate into one place.

The list is something like this in my list.txt file. Each entry starts off on a new line.

 C:\xxx\xxy
 C:\abc\def\ghi.pdf

and my destination folder is c:\\users\\mr_a\\dest

I want to :

1. move the directory xxy and all its files and subfolders to dest

2. move ghi.pdf file to dest .

Do the same for other entries in the list.txt file. So that my dest directory would look like:

dest\xxy
dest\ghi.pdf

I looked into shutil but am not still sure which function to use. It says that the destination directory shouldn't be already existing, but in my case its not so. I'm getting confused which methods to use. Please also mention if the methods you mention are safe (I don't want any nasty cut-n-paste where bits of my files may go missing etc)

What I'm asking is: What methods to use to accomplish what I need to do here?

Edit: And I use Windows, not Linux or any Unix system

Answer 1

with open('list.txt') as f:
    for line in f:
        shutil.move(line, dest)

Answer 2

Check out os and os.path . You will find some useful functions like:

• os.path.exists - checks whether a path exist (like your destination path)
• os.makedirs - creates a directory (including missing parent directory)
• os.path.isdir , os.path.isfile - checks whether the path contains a directory or a file.
• os.path.basename - cuts the filename out of a path
• os.path.join - joins paths (or a path with a filename)

Here is a code example, I didn't try it:

if not os.path.exists(dest):
    os.makedirs(dest)
with open('list.txt', 'r') as f:
    for line in f.readlines():
         filepath = line.strip()
         filename = os.path.basename(filepath)
         shutil.move(filepath, os.path.join(dest, filename))