持有指针的对象的C ++向量

Question

struct Obj
{
    Obj(P *p, int i): m_p(p), m_info(info) {}
    std::auto_ptr<P> m_p;
    int m_info;
};

std::vector<Obj> objects; // error C2558: struct 'Obj' : no copy constructor available...

The problem here resides in auto_ptr , I guess. Everybody knows that it's a bad thing to push auto_ptr into containers, and it's also a bad to push those who holds auto_ptr into containers. It I had no m_info field, I would use boost::ptr_vector<P> objects

How would you suggest to sort it out?

Answer 1

I assume your class Obj is suppose to take ownership of p. Why not, simply use a normal pointer, with RAII (assign m_p in Obj(P *p, int i) and delete it in ~Obj() ) ?

Or you could easily create a ScopedPointer class, like that one http://www.boost.org/doc/libs/1_36_0/libs/smart_ptr/scoped_ptr.htm

Answer 2

您可以自己管理原始指针（在构造函数中分配，在析构函数中释放并实现复制语义-与RAII一致），也可以将指针的类型从std :: auto_ptr更改为std :: shared_ptr / boost :: shared_ptr /其他。