[英]Splitting string with delimiters in C - segmentation fault
I want to write a function that will split a string into a char array. 我想编写一个将字符串拆分为char数组的函数。 I know that the result array will ALWAYS have only two elements - servername and serverport.
我知道结果数组总是只有两个元素 - servername和serverport。 I wrote this, but it gives me "Segmentation fault" after compilation:
我写了这个,但它在编译后给了我“Segmentation fault”:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* splitString(char stringToSplit[])
{
int i = 0;
char serverinfo[2];
char *tmp;
tmp = strtok(stringToSplit, ":");
while (tmp != NULL)
{
serverinfo[i] = tmp;
tmp = strtok(NULL, ":");
i++;
}
return serverinfo;
}
int main(int argc, char **argv)
{
char st[] = "servername:1234";
char *tab = splitString(st);
printf("%s\n", tab[0]);
printf("%s\n", tab[1]);
return 0;
}
char serverinfo[2];
allocates space for two char
s, but you store char*
s there, so make it 为两个
char
分配空间,但是你将char*
存储在那里,所以制作它
char* serverinfo[2];
But you return it from the function, however, the local variable doesn't exist anymore after the function returned, so you need to malloc
it 但是你从函数返回它,但是,函数返回后局部变量不再存在,所以你需要
malloc
它
char **serverinfo = malloc(2*sizeof *serverinfo);
and declare the function as 并将该函数声明为
char **splitString(char stringToSplit[])
for the correct type. 为了正确的类型。
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