将矢量写入文件并将其读回

Question

I'm trying to do some quick and dirty vector serialization, which doesn't work as expected. The problem is a segfault when trying to read the vector from a file. I store the file offset and vector size in the header. Here's the code:

// writing
std::vector<size_t> index;

header.offset = ofs.tellp();
header.size = sizeof(index);
ofs.write((char *) &index[0], sizeof(index)); // pretty bad right, but seems to work   

// reading
std::vector<size_t> index;
index.resize(header.numElements)

ifs.seekg(header.offset);
// segfault incoming
ifs.read((char *) &index[0], header.size);

To be honest I'd surprised if this worked, but I'm not sure what is a proper way to achieve what I want. I'd prefer to stay away from boost, but I'm already using Qt so if QVector or QByteArray would help me somehow I could use these.

Answer 1

sizeof doesn't do what you think it does for the vector . If you want to get the size, in bytes, of the allocated memory for the vector, you can do index.size() * sizeof(size_t) . index.size() is the number of elements in the vector, and sizeof(size_t) is the size of one element in the vector.

The corrected code would be more like (trimming extra stuff):

// writing...
std::vector<size_t> index;

size_t numElements = index.size();
size_t numBytes = numElements * sizeof(size_t); // get the size in bytes
ofs.write((char *) &index[0], numBytes);

// reading...
std::vector<size_t> index;
index.resize(numElements);

ifs.read((char *) &index[0], numBytes); // again, numBytes is numElements * sizeof(size_t)

As for what sizeof(index) really does, it returns the size of the actual vector object. The elements the vector stores are separate from its size. For example:

int* array = new int[500];
// sizeof(array) is the size of the pointer, which is likely 4 or 8 bytes if you're on 32 or 64 bit system

Answer 2

I would try to use a pointer to a vector. You are trying to use a reference to a data type. It might not work if your C++ is trying to be typesafe