Python读取文件中的每个字符串

Question

I have a text file:

1 0 1 0 1 0

1 0 1 0 1 0

1 0 1 0 1 0

1 0 1 0 1 0

I want to be able to retrieve each string and convert it to an integer data type but my piece of code results in ValueError: invalid literal for int() with base 10: ''

tile_map = open('background_tiles.txt','r');

    for line in tile_map:

        for string in line:

             self.type = int(string);

What is the correct way to retrieve the data and convert it successfully?

Answer 1

One thing to remember when iterating through the file is that the newline character is included, and when you try to cast that using int() , you will receive the error you are referencing (because Python doesn't know how to convert it into an integer). Try using something like:

with open('background_tiles.txt', 'r') as f:
    contents = f.readlines()

for line in contents:
    for c in line.split():
        self.type = int(c)

The with is a context manager, and it is generally a more efficient way to deal with files as it handles things like closing for you automatically when it leaves the block. readlines will read the file into a list (each line represented as a list element), and split() splits on the space.

Answer 2

Your line contains string like - "1 0 1 0 1 0" . You need to split your line on space: -

for string in line.split():
    self.type = int(string);