[英]How to group subsequent rows (based on a criteria) and then count them [MySQL]?
Let's say I have such a table (ordered by date): 假设我有这样一张桌子(按日期排序):
id | name | type | date
1 | A | 1 | 01-08-2012
2 | A | 2 | 01-08-2012
3 | B | 1 | 02-09-2012
4 | A | 1 | 01-10-2012
5 | A | 4 | 01-10-2012
6 | A | 5 | 02-10-2012
I want to group subsequent rows that have the same 'name' value and count them: 我想对具有相同“name”值的后续行进行分组并对它们进行计数:
name | count
A | 2
B | 1
A | 3
I was thinking about writing a stored procedure and using cursors, but I was also wondering, if there's a simpler solution, for example using nested SELECTs, etc. 我正在考虑编写存储过程和使用游标,但我也想知道,如果有一个更简单的解决方案,例如使用嵌套的SELECT等。
My question is very similar to: how to group array and count them , but that one concerns PHP. 我的问题非常类似于: 如何对数组进行分组并对它们进行计数 ,但这个问题与PHP有关。
To do that I used a couple of variables, the table structure, I created my own just for testing and it's: 为此,我使用了几个变量,表结构,我创建了自己的仅用于测试,它是:
create table abc (id int, name varchar(20),type int);
insert into abc values
( 1 , 'A' , 1 ),
( 2 , 'A' , 2 ),
( 3 , 'B' , 1 ),
( 4 , 'A' , 1 ),
( 5 , 'A' , 4 ),
( 6 , 'A' , 5 )
the query ended being like this: 查询结束如下:
set @a:='';
set @counter:=1;
set @groupby:=0;
select *,count(REPEATED) from (select name,if(@a=name,@counter:=@counter+1,@counter:=1) as rep,if(@counter=1,@groupby:=@groupby+1,@groupby) as repeated,@a:=name type from abc) as t group by repeated
you can see it works in SQLFIDDLE if you have any question let me know. 如果您有任何疑问,请告诉我,您可以看到它在SQLFIDDLE中有效 。
In the SQLFIDDLE 在SQLFIDDLE中
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