PHP时间和日期解析和差异

Question

I have a PHP string of the following form: "[Fri, 23 Nov 2012 20:00:18 +0000]"

I'd like to ask how much time passed since then, if it's 1 day and 5 hours etc. How can I do it efficiently?

Thanks!!

Answer 1

有效的方法是将字符串转换为unix时间戳，并根据该逻辑执行逻辑。

Answer 2

You can do

<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->d;
?>

DateTime in PHP

Answer 3

Function strtotime returned unixtime for your string Function time return unixtime for current time. Both function return time in seconds. You cat subtracts it and get interval in seconds

<?php
$logtime = strtotime("Fri, 23 Nov 2012 20:00:18 +0000");
$interval = time() - $logtime;
printf("Interval is: %d hours, %d minutes, %d sec.", 
        $interval/3600, ($interval%3600)/60, $interval%60);
?>

Answer 4

$date = str_replace(array('[',']'),'',"[Fri, 23 Nov 2012 20:00:18 +0000]");

$diff = date_diff(date_create() , date_create($date));

echo $diff->format("Difference: %Y-%M-%d %H:%i:%s");