在不使用string.h的情况下逐字逐句打印句子

Question

I'm currently learning how to program in C. As extra practice I was given some problems from my teacher. Here is what my problem is, I have to use this in my program:

 void strSplitTokens (char *s1, char s2[][], int *numWords);

here is the rest of the problem: A call to strSplitTokens breaks string s1 into its words, it then saves each word in a distinct char array, and all the strings are saved in a single array of characters. Also, it saves the number of words using pointers in numWords. print the strings in the main with the following:

For(i=0;i<numWords;i++) printf("%s\n",s2[i]);

If I run it and give it a sentence like I like programming I need it to output:

I

Like

Programming

My main issue is that I was told not to use string.h, I am kind of lost on how to do it without it. Any advice and guidance would is greatly appreciated.

What I have so far is mostly mock up code which makes no sense:

#include <stdio.h>
void strSplitTokens (char *s1, char s2[][], int *numWords);
int main()
{
    printf("Enter a sentence: ");
    strSplitTokens();

 For(i=0;i<numWords;i++) 
{
        printf("%s\n",s2[i]);
}
    return 0;
}
void strSplitTokens (char *s1, char s2[][], int *numWords);
{
    char s1;
    scanf("%s",&s1);
    if( s1 != '\n')
    {
        strSplitTokens();

    }
}

Answer 1

Check character by character. Put the each character in the two dimensional array until space comes.

i=0;j=0;k=0;  
while(s[k]!='\n') {
    if(s[k]!=' ')
    {
        s1[i][j]=s[k];
        k++; 
        j++;
    }
    else{
        j=0;i++;
    }

}