使用JS访问HTML样式属性

Question

How do I get a CSS property from the style attribute of an HTML element (and ignore the stylesheet/computed properties)?

Eg:

<div style="float:left"></div>

function getStyle(element, name) { ... }
getStyle(element, 'float') === 'left';
getStyle(element, 'font-weight') === null;

I don't mind either raw JS or jQuery.

Answer 1

Does this not work for you?

$('div').attr('style');

If you want to parse this further:

var getStyles = function(element) {

    // ensure element has style
    if (! element.attr('style')) {
        return {};
    }

    // init styles
    var styles = {}

    // parse style attr
    $.each(element.attr('style').split(/\s*;\s*/), function(i,style) {
        if (style.length) { // a style string ending in ; will cause an empty pair after splitting
            pair = style.split(/\s*:\s*/);
            styles[pair[0]] = pair[1];
        }
    });

    return styles;
};

A couple tests

// test an element with style attr
var element = $('<div style="float:left"></div>');
console.log(getStyles(element)); //=> {float: "left"}
console.log(getStyles(element).float); //=> left
console.log(getStyles(element).hello); //=> undefined

// test some element without style attr
var element2 = $('<p>hello</p>');
console.log(getStyles(element2).float); //=> undefined
console.log(getStyles(element2).hello); //=> undefined

​// a bit more complex
var element3 = $('<div style="float:left; background-color:red; color:#555; opacity: 0.5 !important;"></div>');
console.log(getStyles(element3)); //=> {float: "left", opacity: "0.5 !important", background-color: "red", color: "#555"} 
console.log(getStyles(element3).float); //=> left
console.log(getStyles(element3).opacity) //=> 0.5 !important;
console.log(getStyles(element3)["background-color"]); //=> red

​

See it working on jsFiddle

​

Answer 2

如果您想使用纯JS，则此示例：

element.style.display = 'none';

Answer 3

You can use

var floating = $('div').css('float');
$('div').css('float','left');

To access each styling parameters with jQuery.

Answer 4

您也可以通过prop()函数访问

$('div').prop('style');

Answer 5

Here's a quick improvement on macek's code.

This function is in the format asked by Petah. Plus, this function breaks as soon as it finds a match, hence eliminating the need to scan the entire "style" attribute.

function getStyle(element, name) {

if (! element.attr('style')) {
    return {};
}
var result= "";

$.each(element.attr('style').split(/\s*;\s*/), function(i,style) {
    if (style.length) { 
        pair = style.split(/\s*:\s*/);
        if(pair[0] == name) {
            result = pair[1];
            return false;
        }
    }
});

return result;
};

Js Fiddle for examples on usage : http://jsfiddle.net/rxpMJ/2/