如何编写仅匹配数字，文本，空格和仅两个特殊字符的正则表达式

Question

如何编写仅匹配数字，文本以及仅匹配这两个特殊字符＃和-[a-zA-Z0-9＃-\\ s] +的任何其他内容的正则表达式

Answer 1

You could a regular expression similar to this

^(\d|[a-z]|[A-Z]|#|-)*$

Below the code I used for checking the regular expression in c#:

string input = @"343243-2df---ds#SFD#FD";
string pattern = @"^(\d|[a-z]|[A-Z]|#|-)*$";

Console.WriteLine(Regex.Match(input, pattern).Success);
Console.ReadLine();

Also, for future reference material, you could see this regular expression site: http://www.regular-expressions.info/

Answer 2

I believe the following pattern would work in C#:

string pattern = @"^[a-zA-Z\d\s#-]*$";

I just tried a couple of test cases in C# interactive:

Regex.Match("", pattern).Success
> true
Regex.Match("asdf 2F#-#-", pattern).Success
> true
Regex.Match("asdf~asdf", pattern).Success
> false

If you don't want to accept an empty string, simply change the * to + in the pattern. Also, you didn't state that you wanted to match whitespace in your question but your example pattern does match whitespace. If you don't want to match whitespace, remove the \\s.

Update : Edited per Rawling's suggestions.

Answer 3

尝试这个：

^([a-z]|[A-Z]|[#]|[0-9]|[-])+$