查找并替换特定模式

Question

I have a large data.frame in which the first column looks like:

"COL"
ELOVL6
ELOVL7
ELP2
EMC1 (includes EG:23065)
EPT1 (includes EG:28042)
ZEB1 (includes EG:29009)

I would like to remove all the (includes EG:...) to have the following output:

"COL"
ELOVL6
ELOVL7
ELP2
EMC1
EPT1
ZEB1

Any suggestion about?

Thanks a lot in advance

Answer 1

 I suppose y your column of the data.frame

 sapply(as.list(y),function(x){gsub("(.*)\\(.*\\)", "\\1", x)})

EDIT

even more simpler

 gsub("(.*)\\(.*\\)", "\\1", x)

Answer 2

You mean something like this....

COL <- c("ELOVL7",
         "ELP2",
         "EMC1 (includes EG:23065)",
         "EPT1 (includes EG:28042)",
         "ZEB1 (includes EG:29009)")

COL <- data.frame(COL)
data.frame(COL=sapply(strsplit(as.character(COL[,1]), split=" "), '[', 1))
     COL
1 ELOVL7
2   ELP2
3   EMC1
4   EPT1
5   ZEB1