简体   繁体   English

如何在JAX-WS Web服务上引发自定义错误?

[英]How to throw a custom fault on a JAX-WS web service?

How do you throw a custom soap fault on a JAX-WS web service? 如何在JAX-WS Web服务上抛出自定义soap错误? How can I specify the faultCode , faultString and detail of the soap fault? 如何指定faultCodefaultString和soap fault的detail Is it possible to set the value of the detail as bean instead of a String ? 是否可以将detail的值设置为bean而不是String

Please note that I'm developing using code-first approach. 请注意,我正在使用代码优先方法开发。

Use the @WebFault annotation. 使用@WebFault批注。

You can see a good example in Using SOAP Faults and Exceptions in Java JAX-WS Web Services - Eben Hewitt on Java . 您可以在Java JAX-WS Web服务使用SOAP故障和异常--Eben Hewitt on Java中看到一个很好的示例。

You will see the example: 你会看到这个例子:

@WebFault(name="CheckVerifyFault",
    targetNamespace="http://www.example.com")
public class CheckVerifyFault extends Exception {

    /**
     * Java type that goes as soapenv:Fault detail element.
     */
    private CheckFaultBean faultInfo;

    public CheckVerifyFault(String message, CheckFaultBean faultInfo) {
        super(message);
        this.faultInfo = faultInfo;
    }

    public CheckVerifyFault(String message, CheckFaultBean faultInfo, 
           Throwable cause) {
        super(message, cause);
        this.faultInfo = faultInfo;
    }

    public CheckFaultBean getFaultInfo() {
        return faultInfo;
    }
}

UPDATE UPDATE

Another way is to declare the typical exception in the throws clause. 另一种方法是在throws子句中声明典型的异常

eg Suppose the following is my exception class: 例如假设以下是我的异常类:

package pkg.ex;

public class FooException extends Exception {

    public FooException(String message, Throwable cause) {
        super(message, cause);
    }

}

And the next class is the service implementation. 下一课是服务实现。

package pkg.ws;

import javax.jws.WebService;
import pkg.ex.FooException;

@WebService(serviceName = "FooSvc")
public class FooService {

    public String sayHello(String name) throws FooException {
        if (name.isEmpty()) {
            Throwable t = new IllegalArgumentException("Empty name");
            throw new FooException("There is one error", t);
        }
        return "Hello, " + name;
    }

}

If my request is: 如果我的要求是:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" 
                  xmlns:ws="http://ws.pkg/">
   <soapenv:Header/>
   <soapenv:Body>
      <ws:sayHello>
         <arg0>Peter</arg0>
      </ws:sayHello>
   </soapenv:Body>
</soapenv:Envelope>

There is no problem: 没有问题:

<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
   <S:Body>
      <ns2:sayHelloResponse xmlns:ns2="http://ws.pkg/">
         <return>Hello, Peter</return>
      </ns2:sayHelloResponse>
   </S:Body>
</S:Envelope>

But... 但...

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" 
                  xmlns:ws="http://ws.pkg/">
   <soapenv:Header/>
   <soapenv:Body>
      <ws:sayHello>
         <arg0></arg0>
      </ws:sayHello>
   </soapenv:Body>
</soapenv:Envelope>

Then... 然后...

<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
   <S:Body>
      <S:Fault xmlns:ns4="http://www.w3.org/2003/05/soap-envelope">
         <faultcode>S:Server</faultcode>
         <faultstring>There is one error</faultstring>
         <detail>
            <ns2:FooException xmlns:ns2="http://ws.pkg/">
               <message>There is one error</message>
            </ns2:FooException>
         </detail>
      </S:Fault>
   </S:Body>
</S:Envelope>
import javax.xml.soap.SOAPFactory;
import javax.xml.soap.SOAPFault;
import javax.xml.ws.soap.SOAPFaultException;
import javax.xml.namespace.QName;
...

SOAPFactory soapFactory = SOAPFactory.newInstance();
SOAPFault soapFault = soapFactory.createFault(
        "Your custom message", 
         new QName("http://schemas.xmlsoap.org/soap/envelope/", "Client")); 
throw new SOAPFaultException(soapFault);

To choose the right fault code, see http://www.tutorialspoint.com/soap/soap_fault.htm . 要选择正确的故障代码,请访问http://www.tutorialspoint.com/soap/soap_fault.htm

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM