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从 XML 列中提取某些值

[英]Extracting certain values from XML column

i have the following sql query:我有以下 sql 查询:

 select         
I.N.value('@DRN', 'varchar(50)') as DRN,
I.N.value('@CR_GUID', 'varchar(50)') AS CR,
I.N.value('@DR_GUID', 'varchar(50)') AS DR,
I.N.value('@AMOUNT', 'money') as Amount,
I.N.value('@DATE', 'Date') as ProDate
from Table as T
cross apply T.column.nodes('/ITEMS/ITEM') as I(N)

Currently it will bring back everything, example:目前它将带回一切,例如:

DRN    CR         DR        Amount        Prodate
12     2p1rf      684pb     4686.23       2012-11-14
12     586io      fdc25     4686.23       2012-11-16
13     hnv7p      19i6f     1800.00       2012-11-20
14     cd7k0      9s2vc      570.50       2012-11-20
15     pm78s      qw3d5     8500.00       2012-11-23

how do i exclude the following from the results, this is from the same row in the xml column?我如何从结果中排除以下内容,这是来自 xml 列中的同一行?

 DRN    CR         DR        Amount        Prodate
*12*     2p1rf      684pb     4686.23       2012-11-14
*12*     586io      fdc25     4686.23       2012-11-16

i only want the query to bring back rows with one item in the xml column not mutliple values.我只希望查询带回 xml 列中的一项而不是多个值的行。

thank you谢谢你

how do i then go about to bring back only the first item in a row with multiple items:那么我如何才能只带回包含多个项目的连续第一项:

 DRN    CR         DR        Amount        Prodate
*12*     2p1rf      684pb     4686.23       2012-11-14
*12*     586io      fdc25     4686.23       2012-11-16

so i want to only see the item with the date 2012-11-14 not everything pertaining to the row?所以我只想看到日期为 2012-11-14 的项目而不是与该行有关的所有内容? i hope that makes sense?我希望这是有道理的?

You should be able to do an inline aggregate and filter on that您应该能够进行内联聚合并对其进行过滤

SELECT
    X.DRN, X.CR, X.DR, X.Amount, X.ProDate
FROM
    (
    SELECT
        COUNT(*) OVER (PARTITION BY I.N.value('@DRN', 'varchar(50)')) AS CountPerDRN,
        I.N.value('@DRN', 'varchar(50)') as DRN,
        I.N.value('@CR_GUID', 'varchar(50)') AS CR,
        I.N.value('@DR_GUID', 'varchar(50)') AS DR,
        I.N.value('@AMOUNT', 'money') as Amount,
        I.N.value('@DATE', 'Date') as ProDate
    from
        MyTable as T
        cross apply
        T.Mycolumn.nodes('/ITEMS/ITEM') as I(N)
    ) X
WHERE
   X.CountPerDRN= 1

Edit, after question addition编辑,添加问题后

Simply change the inline aggregate to a window function只需将内联聚合更改为窗口函数
In this case, I've chosen the row based on the lowest ProDate在这种情况下,我选择了基于最低ProDate的行

SELECT
    X.DRN, X.CR, X.DR, X.Amount, X.ProDate
FROM
    (
    SELECT
        ROW_NUMBER() OVER (
                  PARTITION BY I.N.value('@DRN', 'varchar(50)')
                  ORDER BY I.N.value('@DATE', 'Date')
                  ) AS rnPerDRN,
        I.N.value('@DRN', 'varchar(50)') as DRN,
        I.N.value('@CR_GUID', 'varchar(50)') AS CR,
        I.N.value('@DR_GUID', 'varchar(50)') AS DR,
        I.N.value('@AMOUNT', 'money') as Amount,
        I.N.value('@DATE', 'Date') as ProDate
    from
        MyTable as T
        cross apply
        T.Mycolumn.nodes('/ITEMS/ITEM') as I(N)
    ) X
WHERE
   X.rnPerDRN = 1

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