函数名称周围的括号是什么意思？

Question

In one of my project source files, I found this C function definition:

int (foo) (int *bar)
{
    return foo (bar);
}

Note: there is no asterisk next to foo , so it's not a function pointer. Or is it? What is going on here with the recursive call?

Answer 1

In the absence of any preprocessor stuff going on, foo 's signature is equivalent to

int foo (int *bar)

The only context in which I've seen people putting seemingly unnecessary parentheses around function names is when there are both a function and a function-like macro with the same name, and the programmer wants to prevent macro expansion.

This practice may seem a little odd at first, but the C library sets a precedent by providing some macros and functions with identical names .

One such function/macro pair is isdigit() . The library might define it as follows:

/* the macro */
#define isdigit(c) ...

/* the function */
int (isdigit)(int c) /* avoid the macro through the use of parentheses */
{
  return isdigit(c); /* use the macro */
}

Your function looks almost identical to the above, so I suspect this is what's going on in your code too.

Answer 2

The parantheses don't change the declaration - it's still just defining an ordinary function called foo .

The reason that they have been used is almost certainly because there is a function-like macro called foo defined:

#define foo(x) ...

Using (foo) in the function declaration prevents this macro from being expanded here. So what is likely happening is that a function foo() is being defined with its body being expanded from the function-like macro foo .

Answer 3

The parentheses are meaningless.
The code you show is nothing but an infinite recursion.

When defining a function pointer, you sometimes see strange parentheses that do mean something. But this isn't the case here.