不使用jQuery替换img src属性

Question

i am replacing the img src attribute using javascript

my code is

<div class="reader" id="reader1"></div>    

    <img src="images/img_001.jpg" alt="image" id="image1"/>

</div> 

and javascript code

$("#image1").attr("src").replace("images/img_001.jpg", "images/img_002.jpg");

the src attribute is not replacing

Answer 1

您不需要调用replace() ，只需设置新的src即可：

$("#image1").attr("src", "images/img_002.jpg");

Answer 2

参见http://api.jquery.com/attr/#attr2 ：

$("#image1").attr("src", "images/img_002.jpg");

Answer 3

You can change a value using

$('#image1').attr('src', 'images/img_002.jpg');

If you are using:

$('#image1').attr('src');

The function will return a string. String do NOT get passed by reference, but get copied instead. So modifying it doesn't actually change it.

Answer 4

You can directly set the value of src with:

$("#image1").attr("src", "images/img_002.jpg");

http://jsfiddle.net/VFgn8/

Have a look at jQuery doc for attr() .

Answer 5

or you can use prop()

$("#image1").prop("src", "images/img_002.jpg");

Working Demo

Answer 6

The reason is because the replace method actually returns the new string - not edits it in place.

You can achieve what you want like this:

$("#image1").attr("src", function(){
    return $(this).attr('src').replace("images/img_001.jpg", "images/img_002.jpg");
});

This sets a new value to the src attribute by calling the function (second parameter). This function actiually returns the replaced value.

Live example (check the src with developer tools): http://jsfiddle.net/4K3Dy/