[英]A mysterious compilation error: cannot convert from 'const boost::shared_ptr<T>' to 'const boost::shared_ptr<T>'
I wanted to protect the access to a log file that I use for multithreaded logging with boostlog library. 我想保护对用于带有boostlog库的多线程日志记录的日志文件的访问。
I tried this stream class 我试过这个流类
class ThreadSafeStream
{
public:
template <typename TInput>
const ThreadSafeStream& operator<< (const TInput &tInput) const
{
// some thread safe file access
return *this;
}
};
using it this way (text_sink is a boostlog object): 以这种方式使用它(text_sink是一个boostlog对象):
//...
m_spSink.reset(new text_sink);
text_sink::locked_backend_ptr pBackend = m_spSink->locked_backend();
const boost::shared_ptr< ThreadSafeStream >& spFileStream = boost::make_shared<ThreadSafeStream>();
pBackend->add_stream(spFileStream); // this causes the compilation error
and I get this mysterious error: cannot convert from 'const boost::shared_ptr<T>' to 'const boost::shared_ptr<T>'
我得到了这个神秘的错误:
cannot convert from 'const boost::shared_ptr<T>' to 'const boost::shared_ptr<T>'
the whole compile error: 整个编译错误:
Log.cpp(79): error C2664: 'boost::log2_mt_nt5::sinks::basic_text_ostream_backend<CharT>::add_stream' : cannot convert parameter 1 from 'const boost::shared_ptr<T>' to 'const boost::shared_ptr<T> &'
1> with
1> [
1> CharT=char
1> ]
1> and
1> [
1> T=ThreadSafeStream
1> ]
1> and
1> [
1> T=std::basic_ostream<char,std::char_traits<char>>
1> ]
1> Reason: cannot convert from 'const boost::shared_ptr<T>' to 'const boost::shared_ptr<T>'
1> with
1> [
1> T=ThreadSafeStream
1> ]
1> and
1> [
1> T=std::basic_ostream<char,std::char_traits<char>>
1> ]
1> No user-defined-conversion operator available that can perform this conversion, or the operator cannot be called
I suspect that I am not well defining the operator<<()... but I don't find what is wrong. 我怀疑我没有很好地定义运算符<<()...但我没有发现什么是错的。
this is the prototype of addStream: void add_stream(shared_ptr< stream_type > const& strm);
这是addStream的原型:
void add_stream(shared_ptr< stream_type > const& strm);
with typedef std::basic_ostream< target_char_type > stream_type;
with
typedef std::basic_ostream< target_char_type > stream_type;
From the error message presuably pBackend->add_stream
is expected a shared_ptr
(!) to an ostream
while you're giving it a shared_ptr
to a ThreadSafeStream
which is a totally unrelated type. 从错误消息中可以预期
pBackend->add_stream
是一个shared_ptr
(!)到一个ostream
而你给它一个shared_ptr
到一个完全不相关的ThreadSafeStream
类型。 You'll need to create an overloaded add_stream
method that works with ThreadSafeStream
s most likely. 您需要创建一个重载的
add_stream
方法,该方法最有可能与ThreadSafeStream
一起使用。
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