PHP脚本无法通过Ajax调用执行

Question

i need your help.

i have some input with a button like this.

<input type="text" name="cmsperso" id="cmsperso" />
<input type="text" name="chefdequart" id="chefdequart" />
<input type="text" name="adjoint" id="adjoint" />
<button type="submit" name="perso" onClick="perso()">envoyer</button>

the onClick call an ajax function.

function perso() {
$.ajax({
  type: "POST",
  url: "form/perso.php",
});}

and in my perso.php, i have this update.

$cnx = mysql_connect( "localhost", "root", "" );
$db = mysql_select_db( "maincourante" );
$req = mysql_query("SELECT idops FROM ops ORDER BY idops DESC LIMIT 1");
$data = mysql_fetch_array($req);

$cmsperso = $_POST["cmsperso"];
$chefdequart = $_POST["chefdequart"];
$adjoint = $_POST["adjoint"];

$perso = utf8_decode("UPDATE `Opérations n°".$data['idops']."` SET cmsperso='$cmsperso', chefdequart='$chefdequart', adjoint='$adjoint'");

mysql_query($perso, $cnx) or die(mysql_error());
mysql_close();

all is working fine exept the update. In phpmyadmin none of the value is update.

please help

Answer 1

you are not sending the variable values in your post,

function perso() {
$.ajax({
  type: "POST",
  url: "form/perso.php",
});}

need to add the variable and value to this call like:

function perso() {
$.post("form/perso.php", { adjoint: $("#adjoint").val(), cmsperso: $("#cmsperso").val(), chefdequart: $("#chefdequart").val() } );
});}

also take a look at PDO for managing your data objects as your query can be injected into

finaly it seems you have no where clause, this means that ALL lines in your table will be updated which probably not what you were after.

another think i would consider is naming you table something simpler than it is now having spaces and special charaters in there is asking for trouble.

Answer 2

Are you sure Opérations n°".$data['idops']." is the correct table you are trying to update?

Answer 3

good morning,

i think, i partially resolve my problem

this is my code

function getXMLHttpRequest() {
var xhr2 = null;

if (window.XMLHttpRequest || window.ActiveXObject) {
    if (window.ActiveXObject) {
      try {
        xhr2 = new ActiveXObject("Msxml2.XMLHTTP");
      }
      catch(e) {
        xhr2 = new ActiveXObject("Microsoft.XMLHTTP");
      }
    } 
    else {
      xhr2 = new XMLHttpRequest();
    }
  } 
  else {
    alert("Votre navigateur ne supporte pas l'objet XMLHTTPRequest...");
    return null;
  }
  return xhr2;
}

/* ressources */
function perso() {
  $.post("form/perso.php", { 
    cmsperso: $("#cmsperso").val(), 
    chefdequart: $("#chefdequart").val(),
    adjoint: $("#adjoint").val()
  });

  var xhr2 = getXMLHttpRequest();

  xhr2.open("POST", "form/perso.php", false);
}

and this return in firebug

any idea?