[英]Bash- create an array and increment each index- then the greatest index
know question is not clear at a glance, i have this table: 知道问题一目了然,我有这张表:
ID Start End
1 1 4
2 2 5
3 4 9
4 8 10
I want to set these in an order (illustration below). 我想在订单中设置这些(如下图所示)。 I need an array that its indices will increment by one with respect to start and the end positions, and get the greatest index of all.
我需要一个数组,其索引将相对于开始和结束位置递增1,并获得所有的最大索引。 For example:
例如:
1. ####
2. ####
3. ######
4. ###
so array will be;
array =(1,2,2,3,2,1,1,2,2,1)
i did not start to write anything because i could not figure whether that is possible with bash. 我没有开始写任何东西,因为我无法确定这是否可能与bash。 please advice..
请指教..
Just loop over all the elements of each interval: 只需循环遍历每个区间的所有元素:
#! /bin/bash
array=()
while read id start end ; do
for (( i=start ; i<=end ; i++ )) ; do
let array[i]++
done
done << EOF
1 1 4
2 2 5
3 4 9
4 8 10
EOF
echo "${array[@]}"
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