C中的整数数组初始化错误

Question

I'm trying to initialize my array in the following way but get an expression syntax error:

int LineOne[ARRAY_LENGTH];//where ARRAY_LENGTH is a constant of length 10
if(SOME_CONDITION_IS_TRUE){
LineOne[ARRAY_LENGTH] = {0,1,0,0,1,1,1,0,1,1};
}

Answer 1

You cannot have array literals in "classic" C, except as initializers when the variable is being defined.

In C99, you can use compound literals to do this, but you must repeat the type in a cast-like expression before the literal:

LineOne = (int[ARRAY_LENGTH]) { 0,1,0,0,1,1,1,0,1,1 };

Answer 2

It really depends on the rest of the code (how you want to use the array), what solution is the best. One other way to do it could be...

int* LineOne = 0;
if(SOME_CONDITION_IS_TRUE) {
    static int* init = {0,1,0,0,1,1,1,0,1,1};
    LineOne = init;
}

Answer 3

You can not do it that way. You could use an alternate array and copy it:

#include <string.h>
…
int values[] = {0,1,0,0,1,1,1,0,1,1};

int LineOne[ARRAY_LENGTH];//where ARRAY_LENGHT is a constant of length 10
if(SOME_CONDITION_IS_TRUE)
    memcpy(LineOne, values, sizeof(values));