如何创建家谱？

Question

Having dictionary with family members how can I create a tree of it?

Dictionary have a structure that looks like this:

{'parent':'Smith', 'children':[
    {'parent':'Connor', 'children':[
        {'parent':'Alexis','children':[
            {'parent':'Joe', 'children':[
                {'parent':'Clark','children':[]}]}]},
        {'parent':'Sue','children':[]}]},
    {'parent':'Cooper', 'children':[
        {'parent':'Max','children':[
            {'parent':'Luis', 'children':[]},]},
        {'parent':'Elvis', 'children':[]},
        {'parent':'Steven', 'children':[]}]}]}

After creating family tree, how can I check some dates such as: how to check how many members got entire family or single family of tree.

check how big is entire family tree root or some part of family.

how can I add new members to existing position or to new position inside family tree?

Edit

Adding example of tree:

Smith
    Conor
        Alexis
            Joe
                Clark
        Sue
    Cooper
        Max
            Luis
        Elvis
        Steven

Same style as computer system directory.

Answer 1

This is just inspectorG4dget's answer which was almost there but needs some alterations:

class Person:
    ID = itertools.count()
    def __init__(self, name, parent=None, level=0):
        self.id = self.__class__.ID.next() # next(self.__class__.ID) in python 2.6+
        self.parent = parent
        self.name = name
        self.level = level
        self.children = []

def createTree(d, parent=None, level=0):
    if d:
        member = Person(d['parent'], parent, level)
        level = level + 1
        member.children = [createTree(child, member, level) for child in d['children']]
        return member

t = createTree(my_tree)          # my_tree is the name of your dictionary
def printout(parent, indent=0):
    print '\t'*indent, parent.name
    for child in parent.children:
        printout(child, indent+1)        
printout(t)

As per the comment above, you need to import itertools at the beginning of the programme.

EDIT: A function to flatten the tree should serve for everything else you want to do:

def flatten(parent):
    L = [parent]
    for child in parent.children:
        L += flatten(child)
    return L
flattened_tree = flatten(t)
print "All members: ", [person.name for person in flattened_tree]
print "Number of members:", len(flattened_tree)
print "Number of levels:", max([person.level for person in flattened_tree]) + 1
cooper = flattened_tree[6]
cooper_fl = flatten(cooper)
print "Members below Cooper: ", [person.name for person in cooper_fl]
print "Number:", len(cooper_fl)
levels = [person.level for person in cooper_fl]
print "Number of levels:", max(levels) - min(levels) + 1

Answer 2

Untested, but this should do it

class Person:
    ID = itertools.count()
    def __init__(self):
        self.id = next(self.__class__.ID)
        self.parent = None
        self.children = []

def createTree(familyTreeDict, parent=None):
    if not familyTreeDict:
        return []
    else:
        members = []
        for name familyTreeDict:
            members.append(Person(name))
            members[-1].parent = parent
            for child in familyTreeDict[name]:
                members[-1].children.append(createTree(child, members[-1]))
        return members

Then, if you want to print out a tree structure, given the output from createTree :

def printout(family, indent=0):
    for parent in family:
        print '\t'*indent, parent.name
        for child in parent.children:
            printout(child, indent+1)

Hope this helps