MySQL SELECT两个值之间的行

Question

I need to select data from a mysql database from the past 12 months based on the current date. I have the dates saved in the database as unix timestamps but my query does not seem to work.

$query="SELECT user_id, COUNT(first_name) AS member_count
FROM main_user
WHERE renew_date<'$time' AND renew_date>'$old_time' WHERE renew_date!=''";

Basically I need to count all instances of first_name where there is a renew_date timestamp.

Answer 1

You have an additional WHERE where you should use AND :

$query="SELECT user_id, COUNT(first_name) AS member_count
FROM main_user
WHERE renew_date<'$time' AND renew_date>'$old_time' AND renew_date!=''";
                                                    ^^^

Answer 2

您的查询中有错误，您有两个WHERE子句！

Answer 3

You put WHERE twice . You can use From_UNIXTIME function in mysql

WHERE FROM_UNIXTIME(renew_date)<NOW() 
    AND FROM_UNIXTIME(renew_date)> (NOW()-INTERVAL 1 year)
    AND renew_date !=''

Answer 4

You can find this and other errors, when you test the return value from your query

$query = 'select ...';
$result = $mysqli->query($query);
if ($result === false) {
    // error handling
    echo $mysqli->error;
} else {
    // query successful
    // process result set
}