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如何获取单链列表中元素的索引?

[英]How to get the index of an element in a singly linked list?

I have two classes: 我有两节课:

SLList for methods (private SLElement _root) 方法的SLList(专用SLElement _root)

SLElement for creating new elements for the list. SLElement用于为列表创建新元素。 (public int _value; public SLElement _next) (public int _value; public SLElement _next)

I have finished the add-method: 我已经完成了添加方法:

public void Add(int value)
{
  SLElement addNewElement = new SLElement();
  addNewElement._value = value;
  SLElement rootCopy = _root;
  _root = addNewElement;
  addNewElement._next = rootCopy;
  Console.WriteLine(addNewElement._value);
}

So now I want a remove-function. 所以现在我想要一个删除功能。 I already got it working that it removes an element with a specific value, but I want it so that it removes an element with an specific index. 我已经可以删除具有特定值的元素,但是我希望它可以删除具有特定索引的元素。 How can I find out the index of the elements in my list? 如何找到列表中元素的索引?

您需要从头开始遍历列表,一路计数。

Unless you have a strong reason for which you would like to create your own, I believe you should go for a LinkedList 除非您有充分的理由要创建自己的理由,否则我相信您应该选择LinkedList

var list = new LinkedList<SLElement>();

list.AddAfter(list.AddFirst(new SLElement()), new SLElement());

list.Remove(list.Select((i, j) => new { i, j })
    .Where(j => j.j == 0)//remove the first node
    .Select(i => i.i)
    .FirstOrDefault());

Loop throw index times and find the element 循环抛出索引时间并找到元素

public SLElement Remove(int index)
{
    SLElement prev = _root;
    if(prev == null) return null; //or throw exception
    SLElement curr = _root.next;
    for(int i = 1; i < index; i++)
    {
      if(curr == null) return null; //or throw exception
      prev = curr;
      curr = curr.next;
    }
    prev.next = curr.next; //set the previous's node point to current's next node
    curr.next = null;
    return curr;
}

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