[英]Passing of variable from php to shell script
Here's my php code: 这是我的PHP代码:
<?php
$var1="hello.txt";
exec("expect /home/foo.sh $var1");
?>
and my shell script: 和我的shell脚本:
spawn su -s /bin/bash root -c "/usr/bin/gpg --output /home/$1.gpg --encrypt --recipient sampleonly@yahoo.com /home/$1"
expect "Password:"
send "mypassword\r"
expect "*complete*"
It doesn't get my variable 它没有得到我的变量
You have to assign your arguments to variables like this: 您必须将参数分配给以下变量:
Shell Script: Shell脚本:
set name [lrange $argv 0 0]
send -- "Hello $name"
Terminal command: 终端命令:
expect hello.sh Benjamin
Result: 结果:
Hello Benjamin
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