如何确保从家启动应用程序时启动器活动始终运行

Question

I have 2 activities in my app. The A activity is the launcher one. When I run the app the very first time, the launcher activity runs, but when I press the home button and restart the app from there by clicking the app icon, I always get the B activity running.
I want to make sure that the activity A should always run when starting the app.

This is the manifest code:

 <application
        android:icon="@drawable/icon"
        android:label="@string/app_name" >
        <activity
            android:name="com.velosys.smsManager.Activities.a"
            android:clearTaskOnLaunch="true"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
        <activity android:name="com.velosys.smsManager.Activities.b" />
</application>

I have searched a lot for this but did not get any clue.

Answer 1

也许活动B上的android：launchMode =“ singleInstance”会完成它吗？