包含一个php文件而不显示其内容

Question

Is it possible to include a php file without including its contents? I just want to access the functions and variables in that file without displaying any content. I tried this

<?
    ob_start();
    include('$file');
    ob_end_clean();
?>

But this will hide only contents in php tag. I want to know how to hide others as well.

Answer 1

How to hide? Redesign your solution and separate your concerns! Do not mix logic with UI and so on.

Maybe you should apply the MVC or similar pattern(s).

Answer 2

While I totally agree with Peter's answer

I just tried this because I've never tried it before..

File toinclude.php :

<p>Loads of text</p>
<?php
    function my_test()
    {
        echo 'Hello';
    }
?>
<a href="doesntmatterwhere.php">Ooh a link</a>

File includer.php :

<?php
    ob_start();
    include('toinclude.php');
    ob_end_clean();
    my_test();
?>

And it does work!

Output:

Hello

Answer 3

No you can't.

Include is meant to execute everything inside the file, there are no ways to prevent execution of some part of the file. The only way is to edit the included file.

Answer 4

如果文件未打印任何输出，则可以尝试eval($fileContent) 。