[英]Regex match all inside brackets inside brackets?
I want to find the following value 我想找到以下值
PROCEDURE test {
test { }
}
from: 从:
test {
PROCEDURE test {
test { }
}
}
My current Regex is: 我现在的正则表达式是:
PROCEDURE.*?{.*?(\}){2}
But it does not match. 但它不匹配。 Does anyone have any idea how I can accomplish this? 有谁知道我怎么能做到这一点?
You would need to match pairs of {
and }
between the first {
and the last }
. 您需要在第first {
和last }
之间匹配{
和}
对。
You can try out this regex: - 你可以尝试这个正则表达式: -
PROCEDURE[^{]*[{](?:[^{]*[{][^}]*[}])*[^}]*[}]
I have enclosed curly braces inside character class, so that you don't need to escape them, also with [^{]*
, you won't need reluctant
matching, as it will automatically stop at the first {
. 我在字符类中包含花括号,这样你就不需要使用[^{]*
来转义它们,你不需要reluctant
匹配,因为它会自动停在第一个{
。
What about this regex: 那个正则表达式怎么样:
PROCEDURE\s+\w+\s*\{(?:.*?\{.*?\})*.*?\}
It matches pairs of {}. 它匹配{}对。
However, if the procedure contains strings or comments that contain curly brackets it will fail. 但是,如果过程包含包含大括号的字符串或注释,则它将失败。
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