在不使用Segue的情况下将数据从一个视图控制器传递到另一个

Question

I have a UITableView (let's say class “Parent” which is in view "screen 1"). When I click on one of the Parent's cell's, I'm displaying another UITableView (let's call it class “child” in view “Screen2”). Parent and child are connected through “segue” and I'm able to pass the data using “segue”.

For example, parent is having cell – “Cell1” and on touch “Cell1”, I'm getting “Cell11”,”Cell12”,”Cell13” [this is “ screen2 , table view object”].

Now, there are some descriptions associated with “Cell11” (Once I touched “Cell11”) and i'd like it to display Cell11's description in another view controller (“ screen3 ”). Here, to pass information between “screen2” to “screen3” I'd rather not to use a “Segue” .

How can I do this?

Answer 1

There are two ways in which you can present a new screen.

1) with the interface builder, here you use a segue to pass something onto the new screen.

2) manually instantiating it, after it is instantiated you can just present it.

Considering you do not want to use method 1, you can use method two like this:

ScreenBClass *screenB = [self.storyboard instantiateViewControllerWithIdentifier:@"screenB"];

screenB.objectPointerInOtherClass = self.objectIWantToPass;

[self screenB animated:YES];