OO Javascript .prototype

Question

function Engineer (name, projs, mach) {
    this.base = WorkerBee;
    this.base(name, "engineering", projs);
    this.machine = mach || "";
}
Engineer.prototype = new WorkerBee;

var jane = new Engineer("Doe, Jane", ["navigator", "javascript"], "belau");

This is from a Mozilla example page. Why are there no parentheses for new new WorkerBee? And if the WorkerBee constructor had arguments do we need to pass them in this line to?

Engineer.prototype = new WorkerBee(BaseClassConstructorArgument1,2...)

I had this issue: JS Hint: Missing '()' invoking a constructor.

So I am wondering now, how the clean solution would look like.

Answer 1

Parentheses are optional when calling a constructor using the new keyword, although some linters will warn you. But it's entirely OK to use new WorkerBee instead of new WorkerBee()

If you want to pass arguments, you naturally need the parentheses. That is why some people argue that it's best to always use paratheses for consistency (often the same people that write lint rules).

But the choice is entirely up to you as a programmer.